d. Select a value of a, the probability of a Type I error. Interpret this value in the words of the problem.
d. Select a value of a, the probability of a Type I error. Interpret this value in the words of the problem.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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I need help with only part d. I am using α = .05, but do I reject the null hypothesis or do I fail to reject the null hypothesis? Is there sufficient or insufficient evidence at the significance level α = .05 that the true population

Transcribed Image Text:Stability of compounds in new drugs. Refer to the ACS
Medicinal Chemistry Letters (Vol. 1, 2010) study of the meta-
bolic stability of drugs, Exercise 2.35 (p. 49). Recall that two
important values computed from the testing phase are the
fraction of compound unbound to plasma (fup) and the frac-
tion of compound unbound to microsomes (fumic). A key
formula for assessing stability assumes that the fup/fumic
ratio is 1. Pharmacologists at Pfizer Global Research and
Development tested 416 drugs and reported the fup/fumic
ratio for each. These data are saved in the FUP file, and sum-
mary statistics are provided in the accompanying MINITAB
printout. Suppose the pharmacologists want to determine if
the true mean ratio, u, differs from 1.
a. Specify the null and alternative hypothesis for this test.
b. Descriptive statistics for the sample ratios are provided
in the accompanying MINITAB printout. Note that the
sample mean, x = .327, is less than 1. Consequently,
a pharmacologist wants to reject the null hypothesis.
What are the problems with using such a decision rule?
c. Locate values of the test statistic and corresponding
p-value on the printout.
d. Select a value of a, the probability of a Type I error.
Interpret this value in the words of the problem.

Transcribed Image Text:One-Sample T: RATIO
Test of mu 1 vs not = 1
Variable N Mean StDev SE Mean
RATIO 416 0.3269 0.2915 0.0143
95% CI
I P
(0.2988, 0.3550) -47.09 0.000
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