A>Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 5765 patients treated with this drug. 152 developed the adverse reaction of nausea. Use a 0.01significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction?WSIdentify the null and alternative hypotheses for this test. Choose the correct answer below.OA. Ho: p*0.03H₁: p=0.03ew an example Get more help.OC. Ho: p=0.03H₁: p>0.03B. Ho: p=0.03H₁: p=0.03DOD. Ho: p=0.03H₁: p<0.03двandIdentify the test statistic for this hypothesis test.The test statistic for this hypothesis test is(Round to two decimal places as needed.)XMonroe's Temp....docxRemoved#380F3EDC$4aRFSAMPLE Persuas.pdf%5VTG^6ABMacBook AirY5373255 (1) (1).docxH&78FUN*8JDIIIM(95373255 (1).docx exKO<IH)OLPClear allPcommandV:;ISFIT{+[optionCheck answer?111Show All4191delete

n=5765x=152 Thus, sample proportion p^=1525765=0.0264

Answered: Consider a drug that is used to help…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Show your complete solution II. Use an appropriate statistical tool to test the hypothesis. Use the stepwise method of hypothesis testing. 2. An experimenter was interested in the effect of sleep deprivation on the ability to detect moving objects on a radar screen. The 20 subjects were randomly assigned to one of 4 different conditions (0, 12, 24, 36 hours without sleep). Recorded is the number of failures in spotting moving objects during a test period. Conduct the appropriate test using an alpha of .05. O hrs 12 hrs 24 hrs 36 hrs 36 38 46 76 45 66 20 46 67 62 26 22 61 44 21 40 59 61 74 21
2. Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6079 patients treated with this drug, 153 developed the adverse reaction of nausea. Use a 0.05 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction? Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p#0.03 H:p=0.03 O B. Ho: p= 0.03 H,:p>0.03 O C. Ho: p=0.03 H1: p<0.03 O D. Ho: p= 0.03 H1: p#0.03 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Ho. There is sufficient evidence to warrant rejection of the claim that 3% of users develop nausea. O B. Reject Ho. There is not…
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The Gallup Poll asked 1015 U.S. adults whether they believed that people should pay sales tax on items purchased over the internet. Of these, 477 said they supported such a tax. Does the survey provide convincing evidence that less than 42% of U.S. adults favor an internet sales tax? Use the 0.05 level of significance. 1. STATE THE NULL AND ALTERNATIVE HYPOTHESIS: 2. T STATISTIC/ P VALUE 3.REJECT OR FAIL THE NULL HYPOTHESIS 4. IS THE CLAIM SUPPORTED AT THE 0.05 LEVEL OF SIGNIFICANCE?
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Find the P-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.05 significance level. Is the alternative hypothesis supported? z=3.5 for H₁: μ=124.5 kilograms and H₂: μ# 124.5 kilograms The P-value is (Round to four decimal places as needed.) Determine whether the alternative hypothesis is supported at a 0.05 significance level. O A. The P-value is more than the significance level. Do not reject Ho. The alternative hypothesis is not supported. OB. The P-value is more than the significance level. Reject Ho. The alternative hypothesis is supported. OC. The P-value is less than or equal to the significance level. Reject Ho. The alternative hypothesis is supported. O D. The P-value is less than or equal to the significance level. Do not reject Ho. The alternative hypothesis is not supported.
Consumer Reports did a survey of 1100 adults and found that 565 were unhappy that their food did not look like the picture in the menu. Use a 0.05 significance level to test the claim that the majority of adults are annoyed by food that does not look like the picture in the menu. Identify the null and alternate hypotheses. TTTArial 3 (12pt) v T- = - E·V
Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6225 patients treated with this drug, 164 developed the adverse reaction of nausea. Use a 0.01 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction? OC. Ho:p= 0.03 H4:p>0.03 O D. Ho: p#0.03 H:p=0.03 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is. (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Hn. There is sufficient evidence to warrant rejection of the claim that 3% of users develop nausea. O B. Reject Ho. There is not sufficient evidence to warrant rejection of the claim that 3% of users develop nausea. OC. Fail to reject Ho. There is sufficient evidence to warrant rejection…
Test the claim that the mean GPA of night students is significantly different than 2.5 at the 0.1 significance level. The null and alternative hypotheses would be: Ho p=0.625 Hop=2.5 Ho: p=0.625 Ho: : H₁: p > 0.625 The test is: right-tailed left-tailed two-tailed о :p = 0.625 Hoμ = 2.5 H₁ μ = 2.5 o H₁:μ> 2.5 H₁: p < 0.625 H₁: p0.625 H₁: μ2.5 H₁: μ< 2.5 Based on a sample of 35 people, the sample mean GPA was 2.47 with a standard deviation of 0.06 The p-value is: -1.645 The positive significance level is: .10 Based on this we: OTT Reject the null hypothesis Fail to reject the null hypothesis X (to 3 decimals) o(to 2 decimals)
Using image attached A. Fill in blanks B. What are the null and alternative hypothesis? C. Find the test statistic, z0 D. Find the P-Value
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Test the claim that the proportion of people who own cats is smaller than 60% at the 0.025 significance level. The null and alternative hypothesis would be: Ho: p=0.6 Ho:μ ≥ 0.6 Ho: p 0.6 The test is: left-tailed right-tailed two-tailed Based on a sample of 600 people, 53% owned cats The test statistic is: The p-value is: Based on this we: Ho:p>0.6 Ho: 0.6 Ho: μ 0.6 Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals) (to 2 decimals) =

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