Test the claim that the mean GPA of night students is significantly different than 2.5 at the 0.1 significancelevel.The null and alternative hypotheses would be:Ho p=0.625 Hop=2.5 Ho: p=0.625 Ho::H₁: p > 0.625The test is:right-tailed left-tailed two-tailedо:p = 0.625 Hoμ = 2.5 H₁ μ = 2.5 oH₁:μ> 2.5 H₁: p < 0.625 H₁: p0.625 H₁: μ2.5 H₁: μ< 2.5Based on a sample of 35 people, the sample mean GPA was 2.47 with a standard deviation of 0.06The p-value is: -1.645The positive significance level is: .10Based on this we:OTTReject the null hypothesisFail to reject the null hypothesisX (to 3 decimals)o(to 2 decimals)

Solution: Let X be the GPA. From the given information, x-bar=1.97, S=0.08 and n=35. The given claim…

Answered: Test the claim that the mean GPA of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of men who own cats is significantly different than 15% at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p 0.15 Ho:p= 0.15 Ho:u = Ho:u= Ho:= Ho:p 0.15 o H1:p> 0.15 H:p H:p# H: < H:p 0.15 |3D %3D O.
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.02 significance level. The null and alternative hypothesis would be: Ho:µ 0.8 Ho:p= 0.8 Ho:µ = 0.8 Ho:p > 0.8 H1:µ > 0.8 H1:p > 0.8 H1:µ < 0.8 H1:p 0.8 H1:µ + 0.8 H1:p < 0.8 The test is: two-tailed right-tailed left-tailed Based on a sample of 100 people, 84% owned cats (to 2 decimals) The p-value is: Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the mean GPA of night students is smaller than 2.3 at the 0.05 significance level.The null and alternative hypothesis would be: H0:μ≥2.3H0:μ≥2.3H1:μ<2.3H1:μ<2.3 H0:p=0.575H0:p=0.575H1:p≠0.575H1:p≠0.575 H0:μ=2.3H0:μ=2.3H1:μ≠2.3H1:μ≠2.3 H0:p≤0.575H0:p≤0.575H1:p>0.575H1:p>0.575 H0:μ≤2.3H0:μ≤2.3H1:μ>2.3H1:μ>2.3 H0:p≥0.575H0:p≥0.575H1:p<0.575H1:p<0.575 The test is: two-tailed left-tailed right-tailed Based on a sample of 30 people, the sample mean GPA was 2.26 with a standard deviation of 0.08The test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the mean GPA of night students is significantly different than 3.1 at the 0.1 significance level.The null and alternative hypothesis would be: H0:p=0.775H1:p≠0.775 H0:μ≤3.1H1:μ>3.1 H0:μ≥3.1H1:μ<3.1 H0:μ=3.1H1:μ≠3.1 H0:p≥0.775H1:p<0.775 H0:p≤0.775H1:p>0.775 The test is: two-tailed left-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 3.07 with a standard deviation of 0.07The test statistic is: ? (to 2 decimals)The p-value is: ? (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of people who own cats is significantly different than 50% at the 0.1 significance level.The null and alternative hypothesis would be: H0:μ=0.5H0:μ=0.5Ha:μ≠0.5Ha:μ≠0.5 H0:μ≥0.5H0:μ≥0.5Ha:μ<0.5Ha:μ<0.5 H0:μ≤0.5H0:μ≤0.5Ha:μ>0.5Ha:μ>0.5 H0:p=0.5H0:p=0.5Ha:p≠0.5Ha:p≠0.5 H0:p≥0.5H0:p≥0.5Ha:p<0.5Ha:p<0.5 H0:p≤0.5H0:p≤0.5Ha:p>0.5Ha:p>0.5 Correct The test is: right-tailed two-tailed left-tailed Correct Based on a sample of 300 people, 49% owned catsThe p-value is: Incorrect (to 2 decimals)Based on this we: a) Fail to reject the null hypothesis b) Reject the null hypothesis I am just looking for the correct p-value: (to 2 decimals). The correct answers were p = 0.5 and p does not equal 0.5. This is a two tailed test, and we fail to reject the null hypothesis. I for some reason cannot get the correct p value :,( Reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than 40% at the 0.01 significance level.The null and alternative hypothesis would be: H0:μ=0.4 H0:μ=0.4, H1:μ≠0.4 H1:μ≠0.4, H0:μ=0.4 H0:μ=0.4, H1:μ<0.4 H1:μ<0.4, H0:p=0.4 H0:p=0.4, H1:p≠0.4 H1:p≠0.4 H0:p=0.4 H0:p=0.4, H1:p>0.4 H1:p>0.4, H0:μ=0.4 H0:μ=0.4H1:μ>0.4 H1:μ>0.4, H0:p=0.4 H0:p=0.4, H1:p<0.4 H1:p<0.4 The test is: right-tailed left-tailed two-tailed Based on a sample of 25 people, 32% owned catsThe test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is smaller than 2.4 at the 0.10 significance level. The null and alternative hypothesis would be: Ho:u > 2.4 Ho:p > 0.6 Ho:p 0.6 H1: µ > 2.4 H1:p# 0.6 H1:µ # 2.4 The test is: right-tailed left-tailed two-tailed Based on a sample of 45 people, the sample mean GPA was 2.36 with a standard deviation of 0.08 The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level. The null and alternative hypothesis would be: Ho: HM = HF H,:PM = PF Ho: HM = PF Ho:HM = Pr Ho:PM = Pr Ho:PM PF H1: HM PF H1:HM > HF H1:HM # HF H1:PM + PF H1:PM < Pf The test is: right-tailed two-tailed left-tailed Based on a sample of 40 men, 40% owned cats Based on a sample of 40 women, 65% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 4 decimals) Based on this we: O Reject the null hypothesis OFail to reject the null hypothesis Check Answer
Test the claim that the mean GPA of night students is larger than 2.9 at the 0.025 significance level. The null and alternative hypothesis would be: Ho: µ = 2.9 Ho:u > 2.9 Ho: µ 2.9 H1:p 0.725 The test is: left-tailed right-tailed two-tailed Based on a sample of 25 people, the sample mean GPA was 2.94 with a standard deviation of 0.06 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Add Work
Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.1 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN=μDH0:μN=μDH1:μN>μDH1:μN>μD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:pN=pDH0:pN=pDH1:pN>pDH1:pN>pD H0:pN=pDH0:pN=pDH1:pN<pDH1:pN<pD H0:μN=μDH0:μN=μDH1:μN<μDH1:μN<μD The test is: two-tailed left-tailed right-tailed The sample consisted of 45 night students, with a sample mean GPA of 2.15 and a standard deviation of 0.06, and 35 day students, with a sample mean GPA of 2.16 and a standard deviation of 0.03.The test statistic is: ________(to 2 decimals)The positive critical value is: ________(to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than 60% at the 0.02 significance level.The null and alternative hypothesis would be: H0:μ=0.6H0:μ=0.6H1:μ≠0.6H1:μ≠0.6 H0:p=0.6H0:p=0.6H1:p>0.6H1:p>0.6 H0:p=0.6H0:p=0.6H1:p<0.6H1:p<0.6 H0:μ=0.6H0:μ=0.6H1:μ>0.6H1:μ>0.6 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:μ=0.6H0:μ=0.6H1:μ<0.6H1:μ<0.6 The test is: left-tailed right-tailed two-tailed Based on a sample of 40 people, 65% owned catsThe test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Suppose that at a particular college, a random sample found that 25 out of 100 students who use the internet use Twitter. Does this provide evidence that the true proportion of students at this college who use Twitter is higher than the nationally stated 15%? Use a significance level of 0.05 and the p-value to give your decision. The correct hypotheses to use are: Ho: p = 0.15 HA: p > 0.15 Blank #1: Report the test statistic to two decimal places Blank #2: Report the p-value to four decimal places. Blank #3: Give the test decision: (reject or do not reject) Ho Blank #4: Evidence _[favors or does not favor) that the true proportion of students at this college who use Twitter is higher than the nationally stated 15%.

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