Using image attached A. Fill in blanks B. What are the null and alternative hypothesis? C. Find the test statistic, z0 D. Find the P-Value In a clinical trial, 24 out of 852 patients taking a prescription drug daily complained of flulike symptoms. Suppose that it is known that 2.4% of patients taking competing drugscomplain of flulike symptoms. Is there sufficient evidence to conclude that more than 2.4% of this drug's users experience flulike symptoms as a side effect at the a=0.1 levelof significance?...Because npo (1-Po)> 10, the sample size is greater than 5% of the population size, and the samplefor testing the hypothesis are satisfied.(Round to one decimal place as needed.)=can be reasonably assumed to be random,is given to be random,the requirementscannot be reasonably assumed to be random,is given to not be random,

From the provided information, Sample size (n) = 852 From which 24 taking a prescription drug daily…

Answered: In a clinical trial, 24 out of 852…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of people who own cats is smaller than 10% at the 0.025 significance level.The null and alternative hypothesis would be: Based on a sample of 800 people, 1% owned catsThe test statistic is: (Round to 2 decimals)The p-value is: (Round to 2 decimals)
The p-value for a hypothesis test turns out to be 0.05015. At a 2% level of significance, what is the proper decision? Reject H0H0 Fail to reject H0
A public opinion poll surveyed a simple random sample of voters. Respondents were classified by gender (female or male) and by voting preference (Republican, Democrat, or Independent). The results are presented here: Republican 250 200 Female Male You want to determine if gender and voting preference are independent. Use a level of significance of a = 0.05. Are the requirements met for this hypothesis test? Explain. O Yes. A random sample was used, and all expected counts are greater than or equal to 5. O Yes. A random sample was used, and all observed counts are greater than or equal to 5. O No. A random sample was used, but at least one of the expected counts is less than 5. O No. A random sample was not used. Democrat 300 150 Independent 50 50
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A six-sided die is rolled 120 times. Fill in the expected frequency column. Then, conduct a hypothesis test to determine if the die is fair using 5% significant level. The data in the following table are the result of the 120 rolls. Face Value Frequency Expected Frequency 1 15 2 29 3 16 4 15 5 30 6 15 What are the null and alternate hypotheses?
last box is? or is not?
What is the null hypothesis, alternative hypothesis, p value, and the interpretation of the p value in our everyday words ?
Explain how the P-value is obtained for a one-mean z-test in case the hypothesis test is a. left tailed. b. right tailed. c. two tailed.
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the bone density test scores that can be used as cutoff values separating the lowest 10% and highest 10%, indicating levels that are too low or too high, respectively. Sketch the region containing the lowest 10% and highest 10%. Choose the correct graph below. OA. -Za Za Q The bone density scores are ☐ OB. -Za Za (Use a comma to separate answers as needed. Round to two decimal places as needed.) ○ C. Q Za -Za D. Q a G Za -Za
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Teat the claim abouy the population mean, u, at the given level of significance, a, using the given sample statistics. Claim:u=50; a=0.05; o=3.11. Sample statistics: x=48.4, n=71. i) Identify the null and alternative hypothesis. (Do not forget to find the standardized test statistic and critical values) ii) Determine tge outcome and conclusion of the test.
Which of the following is the name for the statistical hypothesis that describes no change, or nothing expected? Type I error Null hypothesis Type II error Alternative hypothesis

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