According to a survey conducted by the Association for Dressings and Sauces, 20% of American adults eat salad once a week. A nutritionist suspects that this percentage is not accurate. She conducts a survey of 377 American adults and finds that 98 of them eat salad once a week. Use a 0.01 significance level to test the claim that the proportion of American adults who eat salad once a week is larger than 20%. Claim: Select an answer u > 0.2 u ≥ 0.2 u < 0.2 p ≥ 0.2 p ≤ 0.2 p < 0.2 p > 0.2 u ≤ 0.2 p ≠ 0.2 u = 0.2 u ≠ 0.2 p = 0.2 which corresponds to Select an answer H0: p = 0.2 H0: p ≠ 0.2 H0: p ≤ 0.2 H1: p > 0.2 H1: p ≠ 0.2 H1: p < 0.2 H0: u ≥ 0.2 Opposite: Select an answer u = 0.2 u ≤ 0.2 p ≤ 0.2 p = 0.2 p ≠ 0.2 u ≥ 0.2 u ≠ 0.2 u < 0.2 u > 0.2 p > 0.2 p < 0.2 p ≥ 0.2 which corresponds to Select an answer H1: p > 0.2 H0: p ≤ 0.2 H1: p < 0.2 H1: p ≠ 0.2 H0: u ≥ 0.2 H0: p ≠ 0.2 H0: p = 0.2 The test is: Select an answer right-tailed left-tailed two-tailed The test statistic is: zz= (to 2 decimals) The Critical Value is: zz= Based on this we: Select an answer Reject the null hypothesis Fail to reject the null hypothesis Conclusion: There Select an answer does does not appear to be enough evidence to support the claim that the proportion of American adults who eat salad once a week is larger than 20%

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a survey conducted by the Association for Dressings and Sauces, 20% of American adults eat salad once a week. A nutritionist suspects that this percentage is not accurate. She conducts a survey of 377 American adults and finds that 98 of them eat salad once a week. Use a 0.01 significance level to test the claim that the proportion of American adults who eat salad once a week is larger than 20%.

Claim: Select an answer u > 0.2 u ≥ 0.2 u < 0.2 p ≥ 0.2 p ≤ 0.2 p < 0.2 p > 0.2 u ≤ 0.2 p ≠ 0.2 u = 0.2 u ≠ 0.2 p = 0.2  which corresponds to Select an answer H0: p = 0.2 H0: p ≠ 0.2 H0: p ≤ 0.2 H1: p > 0.2 H1: p ≠ 0.2 H1: p < 0.2 H0: u ≥ 0.2

Opposite: Select an answer u = 0.2 u ≤ 0.2 p ≤ 0.2 p = 0.2 p ≠ 0.2 u ≥ 0.2 u ≠ 0.2 u < 0.2 u > 0.2 p > 0.2 p < 0.2 p ≥ 0.2  which corresponds to Select an answer H1: p > 0.2 H0: p ≤ 0.2 H1: p < 0.2 H1: p ≠ 0.2 H0: u ≥ 0.2 H0: p ≠ 0.2 H0: p = 0.2

The test is: Select an answer right-tailed left-tailed two-tailed

The test statistic is: zz= (to 2 decimals)

The Critical Value is: zz=

Based on this we: Select an answer Reject the null hypothesis Fail to reject the null hypothesis

Conclusion: There Select an answer does does not  appear to be enough evidence to support the claim that the proportion of American adults who eat salad once a week is larger than 20%.

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