IV. CENTRAL DOGMA OF MOLECULAR Suppose the following base sequence was found in a 30-base polymer: 3' CAG TTA AGC CTC GGT TAC BIOLOGY 1. What would be the first 10 bases at the 5' end of the complementary strand? CAG GAT ACG GGA 5 Second MRNA base Your answer UCU UUU Phe UGU UAU Tyr UAC Cys UUC Ucc Ser UGC UUA UCA UAA Stop UGA Stop Leu 2. What would be the corresponding MRNA sequence of the given UUG ucG UAG Stop UGG Trp CAU CGU His CUU CCU Cuc polymer? Cc CAC Pro CAA Arg Leu CUA Cua CCA CGA Gin ccG CAG CG Your answer AUU ACU AAU AGU Asn AGC Ser AUC le ACC Thr AAC AUA ACA AGA Lys AGG AAA Arg AUG ACG AAG 3. What would be the resulting amino acid sequence? (Please use the genetic code chart above.) Please GUU GGU Asp GGC GCU GAU GUC GCC GAC Ala GAA Val GUA Gly GCA GGA Glu GGG GUG GCG GAG separate amino acids with "dash" (e.g.phe-leu-ile). Your answer First MRNA base (5' end of codon) Third MRNA base (3' end of codon)

Human Anatomy & Physiology (11th Edition)
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Chapter1: The Human Body: An Orientation
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IV. CENTRAL DOGMA OF MOLECULAR
BIOLOGY
Suppose the following
base sequence was found in a 30-base
polymer: 3' CAG TTA AGC CTC GGT TAC
CAG GAT ACG GGA 5
1. What would be the first 10 bases at
the 5' end of the complementary
strand?
Second MRNA base
Your answer
UUU
UCU
UAU
UGU
Phe
Tyr
UGC
Cys
UUC
UAC
Ser
Ucc
UUA
UCA
UAA Stop UGA Stop
Leu
2. What would be the corresponding
MRNA sequence of the given
UUG
ucG
UAG Stop UGG Trp
CGU
His
CUU
CCu
CAU
Cuc
polymer?
cc
CAC
Pro
CAA
Leu
CUA
Cua
Arg
CCA
CGA
Gin
ccG
CAG
CG
Your answer
AAU
AGU
Asn
AGC
AUU
ACU
Ser
AUC le ACC
AAC
Thr
ACA
AGA
Lys
AGG
AUA
AAA
Arg
AUG
ACG
AAG
3. What would be the resulting amino
acid sequence? (Please use the
genetic code chart above.) Please
separate amino acids with "dash"
(e.g.phe-leu-ile).
GUU
GCU
GAU
GGU
Asp
GGC
GAC
Ala
GAA
GUC
GCC
Gly
Val
GUA
GGA
Glu
GGG
GCA
GUG
GCG
GAG
Your answer
First MRNA base (5 end of codon)
Third MRNA base (3' end of codon)
Transcribed Image Text:IV. CENTRAL DOGMA OF MOLECULAR BIOLOGY Suppose the following base sequence was found in a 30-base polymer: 3' CAG TTA AGC CTC GGT TAC CAG GAT ACG GGA 5 1. What would be the first 10 bases at the 5' end of the complementary strand? Second MRNA base Your answer UUU UCU UAU UGU Phe Tyr UGC Cys UUC UAC Ser Ucc UUA UCA UAA Stop UGA Stop Leu 2. What would be the corresponding MRNA sequence of the given UUG ucG UAG Stop UGG Trp CGU His CUU CCu CAU Cuc polymer? cc CAC Pro CAA Leu CUA Cua Arg CCA CGA Gin ccG CAG CG Your answer AAU AGU Asn AGC AUU ACU Ser AUC le ACC AAC Thr ACA AGA Lys AGG AUA AAA Arg AUG ACG AAG 3. What would be the resulting amino acid sequence? (Please use the genetic code chart above.) Please separate amino acids with "dash" (e.g.phe-leu-ile). GUU GCU GAU GGU Asp GGC GAC Ala GAA GUC GCC Gly Val GUA GGA Glu GGG GCA GUG GCG GAG Your answer First MRNA base (5 end of codon) Third MRNA base (3' end of codon)
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