iv) The phenotype of a double mutant, W X, is shown below. Choose the single regulatory scheme above that is consistent with all of the data. Explain your answer briefly. enzyme activity genotype without fictamine 2 with fictamine 2 strain W X Y Z 1 1 mutant 5 + + ++ ++ ++ ++
iv) The phenotype of a double mutant, W X, is shown below. Choose the single regulatory scheme above that is consistent with all of the data. Explain your answer briefly. enzyme activity genotype without fictamine 2 with fictamine 2 strain W X Y Z 1 1 mutant 5 + + ++ ++ ++ ++
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
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
Transcribed Image Text:### Genetic Influence on Enzyme Synthesis
#### Additional Gene W and Its Effect on Enzyme Synthesis
A study has found an additional gene, called W, that influences the synthesis of enzymes 1 and 2. In this context, a strain identified as mutant d exhibits a recessive mutation in gene W.
#### Genotype and Enzyme Activity Data Table
Below is a detailed table representing different strains and their corresponding genotypes and enzyme activities, both in the presence and absence of a substance called fictamine.
| Strain | Genotype | Enzyme Activity |
|-------------|--------------------|---------------------------------|
| | | Without Fictamine | With Fictamine |
| | W | X | Y | Z | Enzyme 1 | Enzyme 2 | Enzyme 1 | Enzyme 2 |
|-------------|----|----|----|----|-----------------|-----------------|-----------------|-----------------|
| Wild-type | + | + | + | + | ++ | ++ | -- | -- |
| Mutant a | + | – | + | + | -- | -- | -- | -- |
| Mutant b | + | + | – | + | -- | ++ | -- | -- |
| Mutant c | + | + | + | – | ++ | -- | -- | -- |
| Mutant d | – | + | + | + | ++ | ++ | ++ | ++ |
##### Descriptions of Table Contents:
1. **Strains**: This column lists the different genetic strains studied - wild-type, mutant a, mutant b, mutant c, and mutant d.
2. **Genotype**: The genotype of each strain is represented by a '+' or '–', indicating the presence or absence of the active form of genes W, X, Y, and Z, respectively.
3. **Enzyme Activity**:
- Enzyme activity is measured both in the presence and absence of the substance fictamine.
- Symbols indicate the level of enzyme activity: '++' signifies high activity, '--' signifies no activity, and intermediate levels or observations are adjusted accordingly.
##### Key Findings:
- The wild

Transcribed Image Text:**Problem Statement:**
The phenotype of a double mutant, \( W^- X^- \), is shown below. Choose the single regulatory scheme above that is consistent with all of the data. Explain your answer briefly.
**Data Table:**
| | **genotype** | **enzyme activity** |
|:-------------:|:--------------------------------:|:---------------------------:|
| **strain** | W | X | Y | Z | without fictamine | with fictamine |
| | | | | | 1 | 2 | 1 | 2 |
| **mutant 5** | – | – | + | + | ++ | ++ | ++ | ++ |
**Explanation of the Data:**
- The table lists the data for a double mutant strain referred to as "mutant 5."
- The columns under "genotype" describe the presence (+) or absence (–) of four genetic elements (W, X, Y, Z).
- The columns under "enzyme activity" display the activity levels of two enzymes (1 and 2) without and with the presence of a substance called fictamine.
- Enzyme activities are denoted with "++," indicating a high level of activity.
**Task:**
To identify the regulatory scheme that corresponds to the observed data, one must understand how the genotype (presence or absence of W, X, Y, or Z) influences the enzyme activities.
**Observations:**
- Mutant 5 lacks both W and X, but retains Y and Z.
- Despite mutations in W and X, enzyme activity for both enzymes (1 and 2) is high (++) with and without fictamine.
**Conclusions:**
The consistent enzyme activity suggests that W and X do not directly control the activity of enzymes 1 and 2, independently or in combination. Instead, Y and Z may either be directly enhancing enzyme activity or compensating for the absence of W and X.
Therefore, the selected regulatory scheme should consider the possibility that Y or Z override the absence of W and X in maintaining high enzyme activity. Without additional regulatory pattern diagrams, it is challenging to provide the exact scheme, but the outcome suggests Y and Z have a more significant regulatory role in enzyme expression or activation.
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