iv) The phenotype of a double mutant, W X, is shown below. Choose the single regulatory scheme above that is consistent with all of the data. Explain your answer briefly. enzyme activity genotype without fictamine 2 with fictamine 2 strain W X Y Z 1 1 mutant 5 + + ++ ++ ++ ++

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### Genetic Influence on Enzyme Synthesis

#### Additional Gene W and Its Effect on Enzyme Synthesis

A study has found an additional gene, called W, that influences the synthesis of enzymes 1 and 2. In this context, a strain identified as mutant d exhibits a recessive mutation in gene W.

#### Genotype and Enzyme Activity Data Table

Below is a detailed table representing different strains and their corresponding genotypes and enzyme activities, both in the presence and absence of a substance called fictamine.

| Strain      | Genotype           | Enzyme Activity                 |
|-------------|--------------------|---------------------------------|
|             |                    | Without Fictamine | With Fictamine |
|             | W  | X  | Y  | Z |    Enzyme 1   |   Enzyme 2 |   Enzyme 1   |  Enzyme 2 |
|-------------|----|----|----|----|-----------------|-----------------|-----------------|-----------------|
| Wild-type   | +  | +  | +  | +  | ++              | ++              | --              | --              |
| Mutant a    | +  | –  | +  | +  | --              | --              | --              | --              |
| Mutant b    | +  | +  | –  | +  | --              | ++              | --              | --              |
| Mutant c    | +  | +  | +  | –  | ++              | --              | --              | --              |
| Mutant d    | –  | +  | +  | +  | ++              | ++              | ++              | ++              |

##### Descriptions of Table Contents:
1. **Strains**: This column lists the different genetic strains studied - wild-type, mutant a, mutant b, mutant c, and mutant d.
2. **Genotype**: The genotype of each strain is represented by a '+' or '–', indicating the presence or absence of the active form of genes W, X, Y, and Z, respectively.
3. **Enzyme Activity**: 
   - Enzyme activity is measured both in the presence and absence of the substance fictamine.
   - Symbols indicate the level of enzyme activity: '++' signifies high activity, '--' signifies no activity, and intermediate levels or observations are adjusted accordingly.

##### Key Findings:
- The wild
Transcribed Image Text:### Genetic Influence on Enzyme Synthesis #### Additional Gene W and Its Effect on Enzyme Synthesis A study has found an additional gene, called W, that influences the synthesis of enzymes 1 and 2. In this context, a strain identified as mutant d exhibits a recessive mutation in gene W. #### Genotype and Enzyme Activity Data Table Below is a detailed table representing different strains and their corresponding genotypes and enzyme activities, both in the presence and absence of a substance called fictamine. | Strain | Genotype | Enzyme Activity | |-------------|--------------------|---------------------------------| | | | Without Fictamine | With Fictamine | | | W | X | Y | Z | Enzyme 1 | Enzyme 2 | Enzyme 1 | Enzyme 2 | |-------------|----|----|----|----|-----------------|-----------------|-----------------|-----------------| | Wild-type | + | + | + | + | ++ | ++ | -- | -- | | Mutant a | + | – | + | + | -- | -- | -- | -- | | Mutant b | + | + | – | + | -- | ++ | -- | -- | | Mutant c | + | + | + | – | ++ | -- | -- | -- | | Mutant d | – | + | + | + | ++ | ++ | ++ | ++ | ##### Descriptions of Table Contents: 1. **Strains**: This column lists the different genetic strains studied - wild-type, mutant a, mutant b, mutant c, and mutant d. 2. **Genotype**: The genotype of each strain is represented by a '+' or '–', indicating the presence or absence of the active form of genes W, X, Y, and Z, respectively. 3. **Enzyme Activity**: - Enzyme activity is measured both in the presence and absence of the substance fictamine. - Symbols indicate the level of enzyme activity: '++' signifies high activity, '--' signifies no activity, and intermediate levels or observations are adjusted accordingly. ##### Key Findings: - The wild
**Problem Statement:** 
The phenotype of a double mutant, \( W^- X^- \), is shown below. Choose the single regulatory scheme above that is consistent with all of the data. Explain your answer briefly.

**Data Table:**

|               | **genotype**                     | **enzyme activity**         | 
|:-------------:|:--------------------------------:|:---------------------------:|
| **strain**    | W         | X          | Y         | Z          | without fictamine | with fictamine    |
|               |           |            |           |            | 1      | 2         | 1    | 2         |
| **mutant 5**  | –         | –          | +         | +          | ++     | ++        | ++   | ++        |

**Explanation of the Data:**

- The table lists the data for a double mutant strain referred to as "mutant 5."
- The columns under "genotype" describe the presence (+) or absence (–) of four genetic elements (W, X, Y, Z).
- The columns under "enzyme activity" display the activity levels of two enzymes (1 and 2) without and with the presence of a substance called fictamine.
- Enzyme activities are denoted with "++," indicating a high level of activity.

**Task:**
To identify the regulatory scheme that corresponds to the observed data, one must understand how the genotype (presence or absence of W, X, Y, or Z) influences the enzyme activities.

**Observations:**
- Mutant 5 lacks both W and X, but retains Y and Z.
- Despite mutations in W and X, enzyme activity for both enzymes (1 and 2) is high (++) with and without fictamine.

**Conclusions:**
The consistent enzyme activity suggests that W and X do not directly control the activity of enzymes 1 and 2, independently or in combination. Instead, Y and Z may either be directly enhancing enzyme activity or compensating for the absence of W and X.

Therefore, the selected regulatory scheme should consider the possibility that Y or Z override the absence of W and X in maintaining high enzyme activity. Without additional regulatory pattern diagrams, it is challenging to provide the exact scheme, but the outcome suggests Y and Z have a more significant regulatory role in enzyme expression or activation.
Transcribed Image Text:**Problem Statement:** The phenotype of a double mutant, \( W^- X^- \), is shown below. Choose the single regulatory scheme above that is consistent with all of the data. Explain your answer briefly. **Data Table:** | | **genotype** | **enzyme activity** | |:-------------:|:--------------------------------:|:---------------------------:| | **strain** | W | X | Y | Z | without fictamine | with fictamine | | | | | | | 1 | 2 | 1 | 2 | | **mutant 5** | – | – | + | + | ++ | ++ | ++ | ++ | **Explanation of the Data:** - The table lists the data for a double mutant strain referred to as "mutant 5." - The columns under "genotype" describe the presence (+) or absence (–) of four genetic elements (W, X, Y, Z). - The columns under "enzyme activity" display the activity levels of two enzymes (1 and 2) without and with the presence of a substance called fictamine. - Enzyme activities are denoted with "++," indicating a high level of activity. **Task:** To identify the regulatory scheme that corresponds to the observed data, one must understand how the genotype (presence or absence of W, X, Y, or Z) influences the enzyme activities. **Observations:** - Mutant 5 lacks both W and X, but retains Y and Z. - Despite mutations in W and X, enzyme activity for both enzymes (1 and 2) is high (++) with and without fictamine. **Conclusions:** The consistent enzyme activity suggests that W and X do not directly control the activity of enzymes 1 and 2, independently or in combination. Instead, Y and Z may either be directly enhancing enzyme activity or compensating for the absence of W and X. Therefore, the selected regulatory scheme should consider the possibility that Y or Z override the absence of W and X in maintaining high enzyme activity. Without additional regulatory pattern diagrams, it is challenging to provide the exact scheme, but the outcome suggests Y and Z have a more significant regulatory role in enzyme expression or activation.
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