Instruction: mov CL, [1234H] Task: Test how many bytes are executed for this instruction and explain why. Replace CL with CH, ES, BP, SP, and BL one time each. Solution :- I need the continuation of the remaining instructions. Instruction CL executed 4 byte (Displacement because the first byte is the opcode the second byte for Addresses , and the third by te is the Second byte Immediate values It will enter cL and CH
Instruction: mov CL, [1234H] Task: Test how many bytes are executed for this instruction and explain why. Replace CL with CH, ES, BP, SP, and BL one time each. Solution :- I need the continuation of the remaining instructions. Instruction CL executed 4 byte (Displacement because the first byte is the opcode the second byte for Addresses , and the third by te is the Second byte Immediate values It will enter cL and CH
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
[[program emu8086]] I need the continuation of the remaining instructions.
![Instruction:
mov CL, [1234H]
Task:
Test how many bytes are executed for this
instruction and explain why. Replace CL with CH,
ES, BP, SP, and BL one time each.
Solution :-
I need the continuation of the
remaining instructions.
Instruction CL
executed
4 byte (Displacement
because
the first byte is the opcode
the second byte for Addresses
, and the third by te is the
Second byte Immediate values
It will enter cL and CH](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc01fe480-0eb1-4a9e-9261-8ec52fdc7bcc%2Fda956434-5126-47e0-b3c7-6bc213b06d95%2Fp7v7ctm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Instruction:
mov CL, [1234H]
Task:
Test how many bytes are executed for this
instruction and explain why. Replace CL with CH,
ES, BP, SP, and BL one time each.
Solution :-
I need the continuation of the
remaining instructions.
Instruction CL
executed
4 byte (Displacement
because
the first byte is the opcode
the second byte for Addresses
, and the third by te is the
Second byte Immediate values
It will enter cL and CH
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