BJT Output Characteristics For the circuit in Figure 13, determine the AO0 voltage needed to bias the transistor to the edge of saturation (VCE = 0.3V). Rc = 1kQ, RB = 100kQ, ẞ = 150, Q1 = 2N3904, Assume VBE = 0.7V, VCE = 0.3V. If you look at the datasheet for the for DC current gain, hFE, the minimum is 100 and maximum is 300, so we will use ẞ=150. You can also see on the datasheet that the VBE is close to 0.7V which is why we are using 0.7V for the base-to-emitter forward bias voltage drop. +5V GND AO 0 Red (V) DMM RB. Ro Black(COM) 22 Q2 E Figure 13: NPN BJT Output Characteristics Circuit Hint: As explained in the background information, ẞ drops off dramatically as the BJT moves further into saturation. The threshold where this reduction of ẞ occurs is referred to as the edge of saturation and occurs around 0.3V but varies with different types of BJTs. Since it is the edge of saturation, we use the full ẞ value. Solve for IB first by writing a KVL from +5V through Vcë to ground (Keep in mind that VCE is equal to 0.3V for edge of saturation). Solve for Ic. Then solve for IB using ẞ. Once you have IB, you can solve for AO0 by writing another KVL from AO0 through Vв to ground and then solve for AO0.
BJT Output Characteristics For the circuit in Figure 13, determine the AO0 voltage needed to bias the transistor to the edge of saturation (VCE = 0.3V). Rc = 1kQ, RB = 100kQ, ẞ = 150, Q1 = 2N3904, Assume VBE = 0.7V, VCE = 0.3V. If you look at the datasheet for the for DC current gain, hFE, the minimum is 100 and maximum is 300, so we will use ẞ=150. You can also see on the datasheet that the VBE is close to 0.7V which is why we are using 0.7V for the base-to-emitter forward bias voltage drop. +5V GND AO 0 Red (V) DMM RB. Ro Black(COM) 22 Q2 E Figure 13: NPN BJT Output Characteristics Circuit Hint: As explained in the background information, ẞ drops off dramatically as the BJT moves further into saturation. The threshold where this reduction of ẞ occurs is referred to as the edge of saturation and occurs around 0.3V but varies with different types of BJTs. Since it is the edge of saturation, we use the full ẞ value. Solve for IB first by writing a KVL from +5V through Vcë to ground (Keep in mind that VCE is equal to 0.3V for edge of saturation). Solve for Ic. Then solve for IB using ẞ. Once you have IB, you can solve for AO0 by writing another KVL from AO0 through Vв to ground and then solve for AO0.
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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electrical engineering bjt

Transcribed Image Text:BJT Output Characteristics
For the circuit in Figure 13, determine the AO0 voltage needed to bias the transistor to the edge of saturation
(VCE = 0.3V). Rc = 1kQ, RB = 100kQ, ẞ = 150, Q1 = 2N3904, Assume VBE = 0.7V, VCE = 0.3V.
If you look at the datasheet for the for DC current gain, hFE, the minimum is 100 and maximum is 300, so we
will use ẞ=150. You can also see on the datasheet that the VBE is close to 0.7V which is why we are using
0.7V for the base-to-emitter forward bias voltage drop.
+5V
GND
AO 0
Red (V)
DMM
RB.
Ro
Black(COM)
22
Q2
E
Figure 13: NPN BJT Output Characteristics Circuit
Hint: As explained in the background information, ẞ drops off dramatically as the BJT moves further into
saturation. The threshold where this reduction of ẞ occurs is referred to as the edge of saturation and occurs
around 0.3V but varies with different types of BJTs. Since it is the edge of saturation, we use the full ẞ value.
Solve for IB first by writing a KVL from +5V through Vcë to ground (Keep in mind that VCE is equal to 0.3V
for edge of saturation). Solve for Ic. Then solve for IB using ẞ. Once you have IB, you can solve for AO0 by
writing another KVL from AO0 through Vв to ground and then solve for AO0.
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