In excavation for a wall footing, the water table level was lowered from a depth of 1.0 m to a depth of 3.0 m in a clayey soil deposit. Considering that the soil has a water content of 28% when it is fully saturated, and above the water table the (dry) unit weight of the soil is 17 kN/m³. Assuming initially that all of the soil above the water table is dry, then compute the following: 1. The effective stress at a depth of 4.0 m after the lowering of the water table. Take Gs = 2.68. (Hints: w*Gs=Sr*e) 2. The increase in effective stress at a depth of 5 m. (You also need to plot the values of total vertical stress and effective vertical stress against depth before and after lowering the water table.)

Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter12: Shear Strength Of Soil
Section: Chapter Questions
Problem 12.18P
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In excavation for a wall footing, the water table level was lowered from a depth of
1.0 m to a depth of 3.0 m in a clayey soil deposit. Considering that the soil has a
water content of 28% when it is fully saturated, and above the water table the (dry)
unit weight of the soil is 17 kN/m³. Assuming initially that all of the soil above the
water table is dry, then compute the following:
1. The effective stress at a depth of 4.0 m after the lowering of the water table.
Take Gs = 2.68. (Hints: w*Gs=Sr*e)
2. The increase in effective stress at a depth of 5 m.
(You also need to plot the values of total vertical stress and effective vertical stress
against depth before and after lowering the water table.)
Transcribed Image Text:In excavation for a wall footing, the water table level was lowered from a depth of 1.0 m to a depth of 3.0 m in a clayey soil deposit. Considering that the soil has a water content of 28% when it is fully saturated, and above the water table the (dry) unit weight of the soil is 17 kN/m³. Assuming initially that all of the soil above the water table is dry, then compute the following: 1. The effective stress at a depth of 4.0 m after the lowering of the water table. Take Gs = 2.68. (Hints: w*Gs=Sr*e) 2. The increase in effective stress at a depth of 5 m. (You also need to plot the values of total vertical stress and effective vertical stress against depth before and after lowering the water table.)
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