For this exercise consider the single-bay building framing plan shown below. The thickness of the one- way slab spanning between the beams has been determined to be five inches. • • Interior beam design: Assume all beams are simple span and design the typical interior floor beams for moment. Design the beams as rectangular sections. Edge girder: Assume the edge girders are simple span and design the girders for moment. Design the girders as rectangular sections. Use a design (unfactored) live load of 80 pounds per square foot. Include the weight of the slab, beams, and girders in the dead load plus include an additional 10 pounds per square foot of superimposed dead load (weight of ceiling, lights, mechanical ducts, and floor finish). Assume the width of the interior beams is twelve inches. The columns are 15" x 15" and the width of the beams and girders framing to the columns will be the same width as the columns (that is, fifteen inches). Use f'c = 4 ksi and fy = 60 ksi. Include a sketch describing the final beam and girder sections. On your sketch, be sure to indicate - but do not design - the shear reinforcement (that is, the stirrups). edge girder (typ. of 2) 35'-0 edge beam (typ. of 2) 4 spaces @ 8'-0" = 32'-0 Interior beam (typ. of 3) 15"x15" column below (typ. of 4)
For this exercise consider the single-bay building framing plan shown below. The thickness of the one- way slab spanning between the beams has been determined to be five inches. • • Interior beam design: Assume all beams are simple span and design the typical interior floor beams for moment. Design the beams as rectangular sections. Edge girder: Assume the edge girders are simple span and design the girders for moment. Design the girders as rectangular sections. Use a design (unfactored) live load of 80 pounds per square foot. Include the weight of the slab, beams, and girders in the dead load plus include an additional 10 pounds per square foot of superimposed dead load (weight of ceiling, lights, mechanical ducts, and floor finish). Assume the width of the interior beams is twelve inches. The columns are 15" x 15" and the width of the beams and girders framing to the columns will be the same width as the columns (that is, fifteen inches). Use f'c = 4 ksi and fy = 60 ksi. Include a sketch describing the final beam and girder sections. On your sketch, be sure to indicate - but do not design - the shear reinforcement (that is, the stirrups). edge girder (typ. of 2) 35'-0 edge beam (typ. of 2) 4 spaces @ 8'-0" = 32'-0 Interior beam (typ. of 3) 15"x15" column below (typ. of 4)
Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN:9781337094740
Author:Segui, William T.
Publisher:Segui, William T.
Chapter9: Composite Construction
Section: Chapter Questions
Problem 9.2.1P: A W1422 acts compositely with a 4-inch-thick floor slab whose effective width b is 90 inches. The...
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Transcribed Image Text:For this exercise consider the single-bay building framing plan shown below. The thickness of the one-
way slab spanning between the beams has been determined to be five inches.
•
•
Interior beam design: Assume all beams are simple span and design the typical interior floor
beams for moment. Design the beams as rectangular sections.
Edge girder: Assume the edge girders are simple span and design the girders for moment. Design
the girders as rectangular sections.
Use a design (unfactored) live load of 80 pounds per square foot. Include the weight of the slab, beams,
and girders in the dead load plus include an additional 10 pounds per square foot of superimposed
dead load (weight of ceiling, lights, mechanical ducts, and floor finish). Assume the width of the
interior beams is twelve inches. The columns are 15" x 15" and the width of the beams and girders
framing to the columns will be the same width as the columns (that is, fifteen inches).
Use f'c = 4 ksi and fy = 60 ksi.
Include a sketch describing the final beam and girder sections. On your sketch, be sure to indicate - but
do not design - the shear reinforcement (that is, the stirrups).
edge girder
(typ. of 2)
35'-0
edge beam (typ. of 2)
4 spaces
@ 8'-0" = 32'-0
Interior beam
(typ. of 3)
15"x15" column below
(typ. of 4)
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