Calculate the stopping sight distance over the crest of a 1,500-ft vertical curve with a plusgrade of 4.4 percent and a minus grade of 2.3 percent.

Answered: Calculate the stopping sight distance…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A 1 SOLVE AND GIVE THE COMPLETE SOLUTION
A vertical sag parabolic curve connects a -5% grade to a +1% grade that meets at station 10 + 700 with elevation of 60m. The change in grade is 0.4% every 20m. What is the stationing and elevation of the lowest point of the curve?
PROBLEM 6: A highway engineer must stake a symmetrical vertical curve where an entering grade of +0.80% meets an existing grade of -0.40% at station 10 + 100 which has an elevation of 140.36 m. the legth of the curve is known to be 120m.1. Determine the vertical distance between the highest point and PT.2. Determine the elevation at the highest point.
Identify the type of vertical curve (sag or crest) by the following rates of change in grade. -0.5% +4.3% -2.3%
A curve with a -6% downgrade intersects an upward slope of +2%. The elevation at the intersection of these grades at station 50+00 is 550.97 feet. The length of the curve is 800 feet. What would be the elevation of the catch basin?
A +5.2% grade is followed by a -2% grade of a vertical summit parabolic curve at station 2+230 with an elevation of 194.60 m. The parabolic curve is 450 m long. a.) Compute the length of curve per 1-degree change in grade b.) Compute the elevation of the highest point c.) Compute stationing of point C whose elevation is 185.35 m.
A descending gradient of 4 % meets an ascending grade of 1 in 40 where a valley curve of length 200 must to be formed. What will be the distance of the lowest point on the valley curve from its first tangent point?
A 2 SOLVE AND GIVE THE COMPLETE SOLUTION
A 777m equal tangent crest vertical curve has PVC at Sta 17+315 and at elevation 189m. The initial grade is 6.96% and the final grade is -6.21%. Determine the elevation (m) of PVI. Round your answer to 3 decimal places.
solve using grade diagram
Please solve the problem with complete solution and diagram. Thank you. A 2% upgrade meets a 5% downgrade at elevation 34.30m (Sta. 4+520). If the vertical parabolic curve is 100m long, find the stationing of the highest point of the curve and plot the profile of the curve giving all pertinent information thereon. Use 20-m interval each point on the curve
A vertical parabolic happy curve underpass has a grade of -4% followed by a grade of 2% intersecting at Sta. 12+150.60 at elevation of 124.80 m above sea level. The change of grade of the sag curve is restricted to 0.6%. a. Compute the length of curve.

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Calculate the stopping sight distance over the crest of a 1,500-ft vertical curve with a plus grade of 4.4 percent and a minus grade of 2.3 percent.