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10ft Cu(1)=600 psf Clay 1 Ysat = 100 psf Cu(2) 1,000 psf 20 ft Clay 2 Ysat = 110 psf == Cu(3) = 800 psf 30 ft Clay 3 Ysat 105 psf 1) A pipe pile is driven through some clay layers (as shown in the figure) to a depth of 60 ft. The outside dimension of the pipe pile is 20 in, with a wall thickness of 0.250 in. Assume that the water table is at the surface. a) Calculate the net point bearing capacity. b) Calculate the skin resistance by using three different techniques: (1) a method (2) ẞ method (Note: The top two layers are NC, and the bottom clay layer has an OCR = 2.5. The O'R=25° for all three layers). (3) A method c) Calculate the net allowable pile capacity. Use FS = 4.

10ft Cu(1)=600 psf Clay 1 Ysat = 100 psf Cu(2) 1,000 psf 20 ft Clay 2 Ysat = 110 psf == Cu(3) = 800 psf 30 ft Clay 3 Ysat 105 psf 1) A pipe pile is driven through some clay layers (as shown in the figure) to a depth of 60 ft. The outside dimension of the pipe pile is 20 in, with a wall thickness of 0.250 in. Assume that the water table is at the surface. a) Calculate the net point bearing capacity. b) Calculate the skin resistance by using three different techniques: (1) a method (2) ẞ method (Note: The top two layers are NC, and the bottom clay layer has an OCR = 2.5. The O'R=25° for all three layers). (3) A method c) Calculate the net allowable pile capacity. Use FS = 4.

Fundamentals of Geotechnical Engineering (MindTap Course List)
Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN:9781305635180
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Braja M. Das, Nagaratnam Sivakugan
Chapter18: Pile Foundation
Section: Chapter Questions
Problem 18.13P
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10ft Cu(1)=600 psf Clay 1 Ysat = 100 psf Cu(2) 1,000 psf 20 ft Clay 2 Ysat = 110 psf == Cu(3) = 800 psf 30 ft Clay 3 Ysat 105 psf
Transcribed Image Text:10ft Cu(1)=600 psf Clay 1 Ysat = 100 psf Cu(2) 1,000 psf 20 ft Clay 2 Ysat = 110 psf == Cu(3) = 800 psf 30 ft Clay 3 Ysat 105 psf
1) A pipe pile is driven through some clay layers (as shown in the figure) to a depth of 60 ft. The outside dimension of the pipe pile is 20 in, with a wall thickness of 0.250 in. Assume that the water table is at the surface. a) Calculate the net point bearing capacity. b) Calculate the skin resistance by using three different techniques: (1) a method (2) ẞ method (Note: The top two layers are NC, and the bottom clay layer has an OCR = 2.5. The O'R=25° for all three layers). (3) A method c) Calculate the net allowable pile capacity. Use FS = 4.
Transcribed Image Text:1) A pipe pile is driven through some clay layers (as shown in the figure) to a depth of 60 ft. The outside dimension of the pipe pile is 20 in, with a wall thickness of 0.250 in. Assume that the water table is at the surface. a) Calculate the net point bearing capacity. b) Calculate the skin resistance by using three different techniques: (1) a method (2) ẞ method (Note: The top two layers are NC, and the bottom clay layer has an OCR = 2.5. The O'R=25° for all three layers). (3) A method c) Calculate the net allowable pile capacity. Use FS = 4.
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