= (e) Find the velocity, v1, v2 and the mass flow rate, Om,in when d₁ = 80 mm, d₂ 30 mm, and F = 3.5 x 102 N. You many need a calculator (or use MATLAB) to solve the equation.
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- If you don't know the solution please leave it but don't copy from other websitesProblem 3 The velocity field of a fluid particle is given by the expressions и %3D (Ах + Вy)t v = (Cx + Dy)t while the motion of the fluid particle is described on the table shown. Position (x, y) m (1, 1) (2, 1) v (m/s) -1.0 Time (s) u (m/s) 1.5 0.5 1.0 5.0 -1.0 Determine the acceleration (magnitude and direction) of the particle at t = 1.0 s. Hint: Solve for the constants A, B, C, and D in order to fully describe the velocity field.SUBJECT: Dynamics of Rigid Bodies. PLEASE BOX THE FINAL ANSWER The motion of a particle is defined by the relation x = 8t^3 – 8 + 30 sin πt, where x and t are expressed inmillimeters and seconds, respectively. Determine the position, the velocity, and the acceleration of the particlewhen t = 5 s.
- Show the complete solution and the necessary graphs/diagrams. Use 2 decimal places in the final answer. A particle moves that is defined by the parametric equations given below (where x and y are in meters, and t is in seconds). Compute the angular velocity (rad/s) at t = 2 seconds.Show the complete solution and the necessary graphs/diagrams. Use 2 decimal places in the final answer. A particle moves that is defined by the parametric equations given below (where x and y are in meters, and t is in seconds). Compute the radial component of the acceleration (m/s^2) at t = 2 seconds.Please show all steps to solve this problem so your thought process is easy to follow. Also please show all formulas that you used. Subject is fluid mechanics
- TOPIC: FLUID MECHANICS - Dimensional Analysis and Similitude Answer the question neatly and completely. Provide what is neededFluid mechanics question"D.80. Compute the ultimate strength capacity of the positive moment beam design below. f'c= 25.3 MPa, fy= 449.3 MPa, bf= 710 mm, t= 85 mm, hw= 400 mm, bw = 440 mm ds= 10 mm, ct= 30 mm, cb = 35 mm. Steel bar details: compression side at top (single layer): 4 - 16 mm dia. , tension side (double- layered): upper layer is 4 - 25 mm dia. and lower layer is 4 - 25 mm dia."
- Please write the complete solutions. Thumbs-up willl be given! Answer in 4 decimal places. DYNAMICS OF RIGID BODIES! A. The equation below gives the velocity of a particle that moves along a straight line. Find the particle's acceleration at x = π seconds. Write the answer to the nearest whole number and in m/s2.Show the complete solution and the necessary graphs/diagrams. Use 2 decimal places in the final answer. A particle moves that is defined by the parametric equations given below (where x and y are in meters, and t is in seconds). Compute the transverse component of the acceleration (m/s^2) at t = 2 seconds.solve the problem thank you