Based on the given figure, answer the followingquestionsHCH₂OHHOHHOHOHHHOStarchEnergy storagebeta 1, 4HCH₂OHHOHOH HStructural sugarFructoseCH₂OHHOHHOHHOHHHOH OCH₂The monomer of this molecule is?What is the branching point?HOH HHThe name of this polymer in animals?The main glycosidic bond in the chain?The importance of this moleculealpha 1, 4OGlucoseOHalpha 1, 6GalactoseGlycogenHHCH₂OHHOHHOHOHH

Introduction Carbohydrate is a type of biomolecule composed of carbon, hydrogen and oxygen.…

Answered: H CH₂OH H OH H O H OH HH N O Starch…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Two different membrane components are shown in the figure below. HO B A CH3 choline head group C glycerol backbone H3C D hydrocarbon tail CH3 CH3 CH3 B- C- D CH₂ 0 CH3 O CH3 C=O C=O CH-CH₂ What are the molecular modules indicated by the letters A-D? Select from the two options provided for each module. Asterol polar head group CH₂ CH₂ O CH3
[Select] [Select] -0-P=0 0 CH-CH₂ C=O (CH₂)12 (CH₂)10CH 3 CH 3 3-3-3-3- + Ọ–CH,CH,N(CH3)3 CH DE P
PART A. Redraw the table below on the whiteboard. Use your biological molecules handout to fill in the missing information in Column B and C. A) Polymer Protein Carbohydrate B) Monomer (Pick 2 specific monomers and redraw them, drawing their name underneath their structure) C) Additional tasks Redraw just the R group for these structures below How many carbons do each of these sugars have?
5
guanosine and a water bind in the active site, does not matter in which order. The scissile N-1 glycosidic bond between the anomeric carbon and N9 of the base is broken resulting in an oxocarbenium transition state. The leaving group electrons are not protonated, but instead swing up to form a double bond between N9 and C8. The double bond that is already present on the purine swings out on N7 and is protonated by an active site histidine acting as a general acid. An active site aspartate acts as a general base, and deprotonates the water substrate molecule. The deprotonated water is then free to attack the transition state in a manner that will generate an αribose. Draw the active site and show how the mechanism works. You will need to draw 3 or 4 different active site “snap-shots” to show the entire process. Be sure to clearly show the transition state and how it might be stabilized
3
In which of the following membrane lipids is the hydrophobic tail connected to the hydrophilic head by an amide bond? O Spingolipids Phosphoglycerols O None of the options has amide bonds Sterols
Although the first two carbons of fructose and glucose are identical in structure to DHAP and GADP (from glycolysis), DHAP and GADP equilibriate on their in solution to favor the ketone over the aldehyde, while fructose and glucose do not. Why? a)The larger size of the molecule sterically hinders the isomerization b)The larger sugars have more OH groups which hydrogen bond and disrupt isomerization c)The larger sugars cyclize, and there is no carbonyl to isomerize in the cyclic form d)The larger sugars cyclize, and in the cyclic form the hydrogen bonding is very strong e)The larger sugars are less soluble in water than the smaller sugars
Select the hydrophobic part of this molecule. Η Η 56, 45 H-O. -C- -C-H C=O C=0 C=0 CH2 CH, ČH2 CH2 CH, CH2 CH2 CH2 ČH2 CH2 CH2 CH2 CH2 CH2 CH2 CH, CH, CH2 CH2 CH2 CH CH2 CH2 CH CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH, CH2 CH2 CH2 CH2 CH2 CH3 CH3 CH3 Copyright © 2009 Pearson Education, Inc. Selected Coordinates Clear HIC
Number 4.
What would match the best?
Glycosidic bonds are found in Third law Entropy is zero at 0K Enantiomers Maintaining a state of order Second law A pair of molecule that are mirror images Carbohydrates options: Glycosidic bonds are found in Entropy is zero at 0K Maintaining a state of order A pair of molecule that are mirror images

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