Given the following cross-sections (with units in mm): b) t=2 b=25 h=25 t = 1.5 b=20 b=25 t=2 I t = 1.5 a=10 b=15 h-25 b=15 t=3 T h=25 Figure 3: Cross-sections for problem 2. 1. For each of them, calculate the position of the centroid of area with respect to the given coordinate system and report them in the table below. 2. For each of them, calculate the second moments of inertia I... and I, around their respective centroid of area and report them in the table below. Note: use the parallel axes theorem as much as possible to minimize the need to solve integrals. Centroid position x y box Moment of inertia lyy by a) b) c) d) e)
Given the following cross-sections (with units in mm): b) t=2 b=25 h=25 t = 1.5 b=20 b=25 t=2 I t = 1.5 a=10 b=15 h-25 b=15 t=3 T h=25 Figure 3: Cross-sections for problem 2. 1. For each of them, calculate the position of the centroid of area with respect to the given coordinate system and report them in the table below. 2. For each of them, calculate the second moments of inertia I... and I, around their respective centroid of area and report them in the table below. Note: use the parallel axes theorem as much as possible to minimize the need to solve integrals. Centroid position x y box Moment of inertia lyy by a) b) c) d) e)
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter9: Moments And Products Of Inertia Of Areas
Section: Chapter Questions
Problem 9.43P
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