find the temperature distribution of the beam shown below, takke of=0.1 C loko I, and L-1m- Co -10 C° 30 со 9-30tw R = lokw/m²/" 16215° he 5Kwlm² ke T = 250°
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- problem 1.3-9 solution plz....with a stress of 52.89 and diameter of 4cm and thickness of 2mm (P) load of 2MPa how was the answer of 5.289MPa achieved? I am using this to answer another similar question to find the Load (P) i have got the information of stress = 18.70MPa , diameter of 1.3m and wall thickness of 29mmConsider the material Al-$456 It has the following physical ploperties Syleld = 230mPA %3D s-72GPA (modulos elasticity) Oultimate=315 mPA G- 28GPA Cmad vlus rigidity) Tuield =130 mPA Joltimate=185 mPA A Calculate Poisson's ratio B) If we have a following dimensions And Forces 3-0 block of Al-5456 with the Ex =800N X= Bcm Fy=1000N ) Is Our block Safes (consider only plane stes) Dset up the 3 eqetions to find the strains (Ex Ey E2) in each directian E Solve the 3exuations to find the Einal dimensions of our block
- A steel I-beam to is designed under the tank for holding it. You know that the deflection of the beam should be limited in order to provide stability for the structure, Therefore, you start with calculating the deflection of the beam under the weight of the tank that can be assumed as a distributed load as shown below. Giver 0.76 in 0.1 k/in A L = 108 in OB 14.92 in N.A. 0.543 in E = 29000 ksi 10.47 in 28.32 in 0.76 in Find: (a) Using equilibrium, solve for the reactions for the beam. (b) Draw the V, M diagram for the beam shown. Label all key points. (c) Calculate the value of the moment of inertia about the neutral axis. (d) Using the method of integration, calculate the equation of the deflected shape of the beam, y(x). (e) Calculate the maximum deflection of the beam under the weight of the tank.Problem 7: Non-circular cross section shaft related to torque problems are difficult to be solved using the basic theory as for circular shaft. Your role is to make use of FAE to analyze the stress in squared cross section shaft shown in Figure.5. g= 6.5(10%) N/cm? e = 0.035 deg 0.5 cm 0.5 cm 0.5 cm- 0.5 cm Figure.5: Squared cross section shaft applied to torque T as 3D model Provide justified explanation and recommendations to simplify the problem from three-dimensional (3D) to two- dimensional (2D). b. а. If the governing boundary value problem equation of such a problem can be given by: + 2g0 = 0, dy? $(x,y) at boundary is 0 dx2Please give the solution clearly, I will vote it up for your effort thank you in advance. LOVE YOU :)