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A close end tube of thin-walled circular section may be subjected to torque Tand internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by the torque can be calculated as T = T/(2πR²), where the mean radius of the cross section is R (i.e., the radius of the centreline of the wall) and the wall thickness is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>> t, you can approximately assume that the internal radius of the tube is equal to R in the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v. Orr T R P 0zz бее Orr Z бее T Ozz Figure Q3 Centreline of the wall [(a) If the change of the diameter cannot exceed 0.1 m under elastic deformation, calculate the minimum allowable wall thickness of the cylindrical pressure vessel. (P=23.6 MPa, T=0 KN.m, R = 2 m, Young's modulus E = 246 GPa, and Poisson's ratio v = 0.21)] Step-3 The functional relationship between the change of the diameter, DD (units: mm), and wall thickness t(units: mm) can be most accurately expressed as Select one: O 1. DD-282.688/t O 2. DD=424.033/t O 3. DD=343.447/t 4. DD = 686.894/t O 5. DD=1696.130/t O 6. DD-228.965/t 7. DD=848.065/t 8. DD=1373.789/t

A close end tube of thin-walled circular section may be subjected to torque Tand internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by the torque can be calculated as T = T/(2πR²), where the mean radius of the cross section is R (i.e., the radius of the centreline of the wall) and the wall thickness is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>> t, you can approximately assume that the internal radius of the tube is equal to R in the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v. Orr T R P 0zz бее Orr Z бее T Ozz Figure Q3 Centreline of the wall [(a) If the change of the diameter cannot exceed 0.1 m under elastic deformation, calculate the minimum allowable wall thickness of the cylindrical pressure vessel. (P=23.6 MPa, T=0 KN.m, R = 2 m, Young's modulus E = 246 GPa, and Poisson's ratio v = 0.21)] Step-3 The functional relationship between the change of the diameter, DD (units: mm), and wall thickness t(units: mm) can be most accurately expressed as Select one: O 1. DD-282.688/t O 2. DD=424.033/t O 3. DD=343.447/t 4. DD = 686.894/t O 5. DD=1696.130/t O 6. DD-228.965/t 7. DD=848.065/t 8. DD=1373.789/t

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A close end tube of thin-walled circular section may be subjected to torque Tand internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by the torque can be calculated as T = T/(2πR²), where the mean radius of the cross section is R (i.e., the radius of the centreline of the wall) and the wall thickness is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>> t, you can approximately assume that the internal radius of the tube is equal to R in the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v. Orr T R P 0zz бее Orr Z бее T Ozz Figure Q3 Centreline of the wall
Transcribed Image Text:A close end tube of thin-walled circular section may be subjected to torque Tand internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by the torque can be calculated as T = T/(2πR²), where the mean radius of the cross section is R (i.e., the radius of the centreline of the wall) and the wall thickness is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>> t, you can approximately assume that the internal radius of the tube is equal to R in the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v. Orr T R P 0zz бее Orr Z бее T Ozz Figure Q3 Centreline of the wall
[(a) If the change of the diameter cannot exceed 0.1 m under elastic deformation, calculate the minimum allowable wall thickness of the cylindrical pressure vessel. (P=23.6 MPa, T=0 KN.m, R = 2 m, Young's modulus E = 246 GPa, and Poisson's ratio v = 0.21)] Step-3 The functional relationship between the change of the diameter, DD (units: mm), and wall thickness t(units: mm) can be most accurately expressed as Select one: O 1. DD-282.688/t O 2. DD=424.033/t O 3. DD=343.447/t 4. DD = 686.894/t O 5. DD=1696.130/t O 6. DD-228.965/t 7. DD=848.065/t 8. DD=1373.789/t
Transcribed Image Text:[(a) If the change of the diameter cannot exceed 0.1 m under elastic deformation, calculate the minimum allowable wall thickness of the cylindrical pressure vessel. (P=23.6 MPa, T=0 KN.m, R = 2 m, Young's modulus E = 246 GPa, and Poisson's ratio v = 0.21)] Step-3 The functional relationship between the change of the diameter, DD (units: mm), and wall thickness t(units: mm) can be most accurately expressed as Select one: O 1. DD-282.688/t O 2. DD=424.033/t O 3. DD=343.447/t 4. DD = 686.894/t O 5. DD=1696.130/t O 6. DD-228.965/t 7. DD=848.065/t 8. DD=1373.789/t
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