For the network of Fig. 7.93, determine: a. ID, and VGS₂- 18 V b. Vps and Vs. Shockley's equation, VGS ID= Vp) ID Vos V 1- VIDSS VGSQ VG = R₂VDD R₁ + R2 VGS VG-IDRS VDS VDD-ID(RD + Rs) (a) ID = 9 mA, VGS₁ = 0.5 V (b) VDs = 7.69 V, Vs = -0.5 V • 2.2 ΚΩ Dss = 8 mA Vp=-8V • 0.39 ΚΩ 8-4 V FIG. 7.93

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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For the network of Fig. 7.93, determine:
a. ID, and VGS₂-
18 V
b. Vps and Vs.
Shockley's equation,
VGS
ID=
Vp)
ID
Vos V 1-
VIDSS
VGSQ
VG =
R₂VDD
R₁ + R2
VGS VG-IDRS
VDS VDD-ID(RD + Rs)
(a) ID = 9 mA, VGS₁ = 0.5 V (b) VDs = 7.69 V, Vs = -0.5 V
• 2.2 ΚΩ
Dss = 8 mA
Vp=-8V
• 0.39 ΚΩ
8-4 V
FIG. 7.93
Transcribed Image Text:For the network of Fig. 7.93, determine: a. ID, and VGS₂- 18 V b. Vps and Vs. Shockley's equation, VGS ID= Vp) ID Vos V 1- VIDSS VGSQ VG = R₂VDD R₁ + R2 VGS VG-IDRS VDS VDD-ID(RD + Rs) (a) ID = 9 mA, VGS₁ = 0.5 V (b) VDs = 7.69 V, Vs = -0.5 V • 2.2 ΚΩ Dss = 8 mA Vp=-8V • 0.39 ΚΩ 8-4 V FIG. 7.93
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