Please solve in detail SECONDSUse the relay characteristic CO-6 below. The TDS if the relay has TS = 5.0 A, an operating time of 1.5 s and Ip' = 15.0 A would be equal to:CURVE 418246TYPICAL TIME CURVESTYPE CO-6OVER CURRENT RELAY50-60 HERTZSelect one:O a. 1O b. 3○ c. 2○ d. 0.552TIME DIAL SETTING3 4 5 6 7 8 9 10 12 14 16 18 20MULTIPLES OF TAP VALUE CURRENT

Step 1: Given Data:Tap Setting Current TS=5.0 AFault Current If=15.0 AOperating Time t=1.5 sStep 2:…

Answered: SECONDS Use the relay characteristic…

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter14: Phase Failure Relays

Section: Chapter Questions

Problem 1SQ: What is the purpose of phase failure relays?

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For 4 pole d.c machine armature winding with a double layer progressive simplex wave winding with 23 number of slots answer the following: a How many coils are present? b What is the coil span in terms of number of slots? c What is commutator pitch in terms of commutator segments? d How many coils are there between two consecutive commutator segments? e How many parallel paths are present?
Need Help with parts 11 and 12 please. Thank you
Solve all parts.
If we have a 50G ground relay connected to a flux summation CT of 50:5. If we measure the phase currents to be, la = 2002-14° b = 1982-120° Ic=77z+120° How much current will flow into the 50G relay?
Find the line fault current of the feeders shown in the figure and the T.S.M of Relay 2. Knowing that actual time of operation of Relay 2 is 1.4 Sec, the time margin between the two relays is 0.6 Sec, and the time setting multiplier (T.S.M.) of Relay 1 is 0.4. Use the I.D.M.T curve shown below. Bec 500/5 00/S CB2 Relay 2 160% Relay 1 120% PSM
What is the purpose of phase failure relays?
Problem 2 - A 1000 – MVA, 20 – kV, 60 – Hzthree-phase generator is connected through a 1000 – MVA, 20 – kVA/345 – kVYtransformer to a 345 – kVcircuit breaker and a 345 – kVtransmission line. The generator reactances are X = 0.15, Xa = 0.3, Xa = 1.4(pu) and its time constants are Ta = 0.05, Ta = 1.0, TA = 0.1(s). The transformer series reactance is 0.06pu; transformer losses and exciting currents are neglected. A three-phase bolted fault (solid 3-phase phase short circuit) occurs on the line side of the circuit breaker when the generator is operated at rated terminal voltage and at no-load. The breaker interrupts the fault 3 cycles after fault inception (neglect the effect of the transformer on generator time constants.) Determine the following (a) The subtransient current (p.u.) through the breaker (b) The sub-transient current (kA) through the breaker (c) The RMS ac (symmetric) fault current (p.u.) after 3 cycles
Please solve d, e, f ONLY.
Please solve in detail to understand
Draw a block diagram of a phase-locked loop (PLL) and briefly explain its operation.
Ex: Consider a A/Y - Connected, 15-MVA, 33 / 11 -KV transformer with differential protection applied, For the current transformer notes ratios show in figure d.36. Calculate the relay currents on full load. Find the minimum relay Current setting to allow 125 percent overload. 33/11 Kv 300/5A 2000/5A faz m AAAA E C An tp ir m is
The role of a Relay in protection scheme is

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