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For each of the following, decide whether the claim is True or False and select the True ones: Suppose we discover that the 3SAT can be solved in worst-case cubic time. Then it would mean that all problems in NP can also be solved in cubic time. If a problem can be solved using Dynamic Programming, then it is not NP-complete. Suppose X and Y are two NP-complete problems. Then, there must be a polynomial-time reduction from X to Y and also one from Y to X.

For each of the following, decide whether the claim is True or False and select the True ones: Suppose we discover that the 3SAT can be solved in worst-case cubic time. Then it would mean that all problems in NP can also be solved in cubic time. If a problem can be solved using Dynamic Programming, then it is not NP-complete. Suppose X and Y are two NP-complete problems. Then, there must be a polynomial-time reduction from X to Y and also one from Y to X.

Operations Research : Applications and Algorithms
Operations Research : Applications and Algorithms
4th Edition
ISBN:9780534380588
Author:Wayne L. Winston
Publisher:Wayne L. Winston
Chapter18: Deterministic Dynamic Programming
Section: Chapter Questions
Problem 10RP
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For each of the following, decide whether the claim is True or False and select the True ones: Suppose we discover that the 3SAT can be solved in worst-case cubic time. Then it would mean that all problems in NP can also be solved in cubic time. If a problem can be solved using Dynamic Programming, then it is not NP-complete. Suppose X and Y are two NP-complete problems. Then, there must be a polynomial-time reduction from X to Y and also one from Y to X.
Transcribed Image Text:For each of the following, decide whether the claim is True or False and select the True ones: Suppose we discover that the 3SAT can be solved in worst-case cubic time. Then it would mean that all problems in NP can also be solved in cubic time. If a problem can be solved using Dynamic Programming, then it is not NP-complete. Suppose X and Y are two NP-complete problems. Then, there must be a polynomial-time reduction from X to Y and also one from Y to X.
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