Suppose the state of the RAM is as follows and the adjacent assembly codewill execute:RAM031220فيا364565141234567$1A = MA = MA = MD = M@4M = DWhat will be the value of the RAM[4] following the assembly codeexecution?

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Answered: Suppose the state of the RAM is as…

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter12: Points, Classes, Virtual Functions And Abstract Classes

Section: Chapter Questions

Problem 19SA

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Please solve this problem in emu8086 microprocessor in Assembly Language. Please solve properly, will upvote after getting proper solve Read 10 inputs (range 0-9) from the user and store them in an array. Find the position (or index) of the maximum and minimum values in the array, and swap them (move the biggest element to the position of the smallest, and move the smallest element to the position of the biggest), and print that again. If there are multiple maximum or minimum numbers, then choose the first occurrence, values. Your program should be able to handle negative values. Explanation: Here from the given input we see that 9 is the maximum number and it has occurred twice, first in the 2nd index and again in the 5th index. Similarly here 3 is the least and it also has appeared twice, once in the 3rd index and again in the 6th index. So we swap 9 and 3 from the 2nd and 3rd indices and then after swapping, print the new array. Input: 7935935874 Output: 7395645874 Comment:Range 0…
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The following byte sequence is the machine code of a program function compiled with the Y86- 64 instruction set. The memory address of the first byte is 0x300. Note that the byte sequence is written in hex-decimal form, i.e., each number/letter is one hex-decimal number representing 4 binary bits, and two numbers/letters represent one byte. 630030F3020000000000000030F11E000000000000007023030000000 00000601061316211761F0300000000000090- Please write out the assembly instructions (in Y86-64 instruction set) corresponding to the machine codes given by the above bytes sequence, and explain what this program function is computing. The machine has a little-endian byte ordering.
Design a Read Only Memory (ROM) to implement the following, A097803, polynomial A=3(2x2 +1), with input (x): 0≤(x)≤7 (a) What is the size of the initial (unsimplified) ROM ? (b) What is the size of the final (simplified) ROM ? (c) Show in detail the final ROM layout, using LogiSim.
Given rax = 0x0000000200000100, rbx = 0x0000000000000100, and rcx = 0x0000000000000001,and the following values in memoryaddress -> byte at that address0x0000000000000100 -> 0x010x0000000000000101 -> 0x000x0000000000000102 -> 0x000x0000000000000103 -> 0x000x0000000000000104 -> 0x020x0000000000000105 -> 0x000x0000000000000106 -> 0x000x0000000000000107 -> 0x00what is the new value in %rax after the following operation?subq -0x04(%rbx, %rcx, 4), %rax
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