Answer the question using matlab and show your steps & work Read the example below carefully, understand how 3d quiver plots are generated. And answer the following twoquestions.% Define a 3D grid of points[x, y, z] = meshgrid(-5:1:5, -5:1:5, -5:1:5);% Define the components of the vector fieldU = -y.* exp(-0.1 * (x.^2 + y.^2 + z.^2));V = x.* exp(-0.1 * (x.^2 + y.^2 + z. ^2));W z. exp(-0.1 * (x.^2 + y.^2 + z. ^2));% Create a 3D quiver plotfigure;quiver3(x, y, z, U, V, W, 0.5); % 0.5 scales the vectors for better visualization% Customize the plottitle('3D Quiver Plot');Bxlabel('X-axis');ylabel('Y-axis');zlabel('Z-axis');axis equal;Question 5. What type of data format is suitable for 3D quiver plotting?Question 6. Please provide two engineering examples that 3D quiver plotting is most appropriate for. Pleaseinclude rationales for your choice.

Question 5: What type of data format is suitable for 3D quiver plotting?In 3D quiver plotting, the…

Answered: Read the example below carefully,…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Although the plot function is designed primarily for plotting standard xy graphs, it can be adapted for other kinds of plotting as well. b. Make a plot of the curve, which is defined parametrically by the equations x = 2cosθ + cos2θ, y = 2sinθ - sin2θ, where 0 < θ < 2π. Take a set of values of θ between zero and 2π and calculate x and y for each from the equations above, then plot y as a function of x. b. Taking this approach a step further, one can make a polar plot r = f(θ) for some function f by calculating r for a range of values of θ and then converting r and θ to Cartesian coordinates using the standard equations x = r cosθ, y = r sinθ. Use this method to make a plot of the function r = ecosθ – 2 cos(4θ) + sin5 (θ/12) in the range 0 <= θ <= 24π. use python code to answer the highlight one
2.
Party hearing. As the number of people at a party increases, you must raise your voice for a listener to hear you against the background noise of the other partygoers. However, once you reach the level of yelling, the only way you can be heard is if you move closer to your listener, into the listener's “personal space.” Model the situation by replacing you with an isotropic point source of fixed power P and replacing your listener with a point that absorbs part of your sound waves. These points are initially separated by ri = 1.40 m. If the background noise increases by Δβ = 4.60 dB, the sound level at your listener must also increase. What separation rf is then required?
Interesting, Intersecting def squares_intersect (s1, s2): An axis-aligned square on the two-dimensional plane can be defined as a tuple (x, y, r) where (x, y) are the coordinates of its bottom left corner and r is the length of the side of the square. Given two squares as tuples (x1, yl, r1) and (x2, y2, r2), this function should determine whether these two squares intersect by having at least one point in common, even if that one point is the shared corner point of two squares placed kitty corner (The intersection of two squares can have zero area, if the intersection consists of parts of the one-dimensional edges.) This function should not contain any loops or list comprehensions of any kind, but should compute the result using only integer comparisons and conditional statements. This problem showcases an idea that comes up with some problems of this nature; it is actually far easier to determine that the two axis-aligned squares do not intersect, and negate that answer! Two squares…
The purpose of this project is to assess your ability to (JAVA): Implement a graph abstract data type. The getDistance method should print the distance of all connected nodes/ vertices. A graph is a set of vertices and a set of edges. Represent the vertices in your graph with an array of strings: Represent the edges in your graph as a two-dimensional array of integers. Use the distances shown in the graph pictured here.Add the following functions to your graph class: A getDistance function that takes two vertices and returns the length of the edge between them. If the vertices are not connected, the function should return the max value for an integer. A getNeighbors function that takes a single vertex and returns a list of all the vertices connected to that vertex. A print method that outputs an adjacency matrix for your graph. Write a test program for your Graph class.
int binsearch (int X , int V [] , int n ) { int low , high , mid , i ; low = 0; high = n - 1; for ( i = 0; i < high ; i ++) { if( V[ i ] > V [ i +1]) return -2; } while ( low <= high ) { mid = ( low + high )/2; if ( X < V [ mid ]) high = mid - 1; else if ( X > V [ mid ]) low = mid + 1; else return mid ; } return -1; } This code takes as input a sorted array V of size n, and an integer X, if X exists in the array it will return the index of X, else it will return -1. 1. Draw a CFG for binsearch(). 2. From the CFG, identify a set of entry–exit paths to satisfy the complete statement coverage criterion. 3. Identify additional paths, if necessary, to satisfy the complete branch coverage criterion. 4. For each path identified above, derive their path predicate…
Interesting, intersecting def squares_intersect(s1, s2): A square on the two-dimensional plane can be defined as a tuple (x, y, r) where (x, y) are the coordinates of its bottom left corner and r is the length of the side of the square. Given two squares as tuples (x1, y1, r1) and (x2, y2, r2), this function should determine whether these two squares intersect, that is, their areas have at least one point in common, even if that one point is merely the shared corner point when these two squares are placed kitty corner. This function should not contain any loops or list comprehensions of any kind, but should compute the result using only integer comparisons and conditional statements.This problem showcases an idea that comes up with some problems of this nature; it is actually far easier to determine that the two squares do not intersect, and negate that answer. Two squares do not intersect if one of them ends in the horizontal direction before the other one begins, or if the same…
Interesting, intersecting def squares_intersect(s1, s2): A square on the two-dimensional plane can be defined as a tuple (x, y, r) where (x, y) are the coordinates of its bottom left corner and r is the length of the side of the square. Given two squares as tuples (x1, y1, r1) and (x2, y2, r2), this function should determine whether these two squares intersect, that is, their areas have at least one point in common, even if that one point is merely the shared corner point when these two squares are placed kitty corner. This function should not contain any loops or list comprehensions of any kind, but should compute the result using only integer comparisons and conditional statements. This problem showcases an idea that comes up with some problems of this nature; it is actually far easier to determine that the two squares do not intersect, and negate that answer. Two squares do not intersect if one of them ends in the horizontal direction before the other one begins, or if the same…
Complete code and solve 8. Given an array nums, there is a sliding window of size kwhich is moving from the very left of the array to the very right.You can only see the k numbers in the window.Each time the sliding window moves right by one position. For example,Given nums = [1,3,-1,-3,5,3,6,7], and k = 3. Window position Max--------------- -----[1 3 -1] -3 5 3 6 7 3 1 [3 -1 -3] 5 3 6 7 3 1 3 [-1 -3 5] 3 6 7 5 1 3 -1 [-3 5 3] 6 7 5 1 3 -1 -3 [5 3 6] 7 6 1 3 -1 -3 5 [3 6 7] 7Therefore, return the max sliding window as [3,3,5,5,6,7]."""import collections def max_sliding_window(nums, k): """ :type nums: List[int] :type k: int :rtype: List[int] """ if not nums:.
Can you help me solve this and explain it step by step on how the answer was found please. Given integer vector x has 5 elements with values 4, 7, 3, 0, 8. What are ending values x? int i ; for ( i == 0; i < x.sixe () - 1; ++i) { x.at(i) = x.at(i); }
f : {1, 2, 3} ® {a, b, c, d} f(1) = c f(2) = b f(3) = a g : {a, b, c, d} ® {x, y, z} g(a) = y g(b) = x g(c) = x g(d) = z Find the composition gof
Need help writing this code based off of the last checkpoints code: Last code in image. Checkpoint B For Checkpoint B you will extend Checkpoint A to do the following: Prompts the user for an additional parameter: the bound on the timescale n of the simulation If a user inputs a negative timescale, the program should immediately print an error message and exit. The program will calculate k,u for every time i<n and output these populations at each step If the population grows negative, treat it as population that has become zero.

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