Q9.21 PointThis is the church encoding for if false then false else true: (Ax.Ay.y) (Ax.Ay.y) (Ax.Ay.x). What isthe beta-normal form of this expression?(Ax.Ay.y) (Ax.Ay.y) (Ax.Ay.x)λκ.λγ.κAx.Ay.yAy-yIt produces an infinite loop.Save AnswerQ9.31 PointWhich of the following lambda expressions correctly representsif false then (if false then false else true) else false?○ (Ax.Ay.y)(x.Ay.y)(λx.λy.x)(λx.λy.x)(\x.\y.x)(\x.\y.y)((\x.\y.y)(\x.\y.y)(^x.Лy.x))© (Ax.Ay.y)((Ax.Ay.y)(Ax.Ay.y)(Ax.Ay.x))(Ax.λy.y)○ (Ax.Ay.y)(x.Ay.x)(λx.λy.y)(^x.λy.x) Q93 PointsGiven the following Church encodings:True: Ax.Ay.xFalse: Ax.Ay.yIf a Then Else c: abcQ9.11 PointWhich of the following represents if true then false else true ?(Ax.Ay.y) (Ax.Ay.x) (Ax.Ay.y)(Ax.Ay.x) (Ax.Ay.y) (Ax.Ay.x)(Ax.Ay.x) (Ax.Ay.y) (Ax.Ay.y)(Ax.Ay.y) (Ax.Ay.y) (Ax.Ay.x)Save Answer

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Answered: Q9.2 1 Point This is the church…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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ISBN-13 is a new standard for identifying books. It uses13 digits d1d2d3d4d5d6d7d8d9d10d11d12d13. The last digit d13 is a checksum, which iscalculated from the other digits using the following formula: 10 - (d1 + 3d2 + d3 + 3d4 + d5 + 3d6 + d7 + 3d8 + d9 + 3d10 + d11 + 3d12)%10If the checksum is 10, replace it with 0. Your program should read the input as astring. Here are sample runs: Enter the first 12 digits of an ISBN-13 as a string: 978013213080 ↵EnterThe ISBN-13 number is 9780132130806
6-In the representation Complement to 1, we the number when Code the absolute value thus is negative: A = True B- False 7- The result in base 10' A - 44.25 B-42015 C- 51. 13 45. 75 8- The result AT 40. B + 61 q of the transformation (101001.10) 2 usi o the transformation (52) a in bose 10 is: C² 42 D-41 WWW 30 O
Question Compute a Huffman trie for the following string of length 61. UUJCUJUVAJHHVUJJUUHEUVJJAVHUJEJEJVUVEUAVJVAAVHJEJJJEHVJJEJHHU Here are the frequencies of the characters in the string: char freq А C 1 7 H 8. J 18 U 12 V 10 Using the encodings from the Huffman trie you computed, how many bits are needed to encode the above string? Do not count the bits to represent the encoding table (or any bits used for padding and byte alignment). Answer Your answer should be a positive integer.
(2) {w = {0, 1]* : w corresponds to the binary encoding, without leading O's, of natural numbers that are powers of 4} Testing strings: €, 0, 1, 01, 10, 11, 100, 101, 1000, 1010, 10000 The accepted strings are: L [ E 01 11 100 101 1000 1010 10000
8. We have the following code word: 01111010101. This string has 7 data bits, plus 4check bits. We are using an error-correcting code that can correct single bit errors.In fact, there is a single bit error in this code. Assuming the use of the Hammingalgorithm, locate the bit that has been altered.
57. In a binary Hamming Code the number of check digits is r then number of message digits is equal to : a. 2^r – 1 b. 2^r – r – 1 c. 2^r – r + 1 d. 2^r + r – 1
ISBN-13 is a new standard for identifying books. It uses 13 digits d1d2d3d4d5d6d7d8d9d10d11d12d13. The last digit d13 is a checksum, which is calculated from the other digits using the following formula: 10 - (d1 + 3d2 + d3 + 3d4 + d5 + 3d6 + d7 + 3d8 + d9 + 3d10 + d11 + 3d12)%10 If the checksum is 10, replace it with 0. Your program should read the input as a string.
True or false: A dataword (k) and a codeword (n) vary in that the k=n+FCS (Frame Check Sequence).
P09.
Create an RLE class that employs fixed-length encoding to compress ASCII bytestreams with a limited number of characters, including the code as part of the encoded bitstream. Add code to compress() to generate a string alpha containing all of the different characters in the message and use it to generate an Alphabet for use in compress(), prepend alpha (8-bit encoding plus its length) to the compressed bitstream, and then add code to expand() to read the alphabet before expansion.
Q1: A bit stream X is transmitted using the standard CRC method, where, X is the 8 bit ASCII of last two digit of your arid number and divisor will be the 8 bit ASCII of last digit of your registration year (For example a student having 19-arid-121 will use ASCII of 21 as X and ASCII of 8 as divisor). [Note: remove the left most 0’s from X as well as divisor]. Write down the complete procedure to create codeword at sender side and then check at receiver side that either the data received is correct or not?
in the example, what is the encoding of the word DUM?

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