translate the following java code: int n = 1; n++; n=n+10; into Hack ALU assembly code
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translate the following java code:
int n = 1;
n++;
n=n+10;
into Hack ALU assembly code
Step by step
Solved in 2 steps
- Write a RISC-V code for the following C code: #define size 1024 int main () { int reps, int step, option, i; reps=10; step=2; option=1; char a[size]; for (i=0; reps;i++) { for (j=0;jint total; int i; total = 0; for (i = 10; i > 0; i--) { total + i; } The following translates this into ARM assembler: /* -- sum-to-ten.s */ .text .global start _start: mov rº, #0 mov r1, #10 again: end: add r0, r0, r1 subs r1, r1, #1 bne again mov r7, #1 swi 0 @r0 := 0 @r1 = 10 @r0 := r0 + r1 @ r1 := r1 - 1 @loop again if we haven't hit zero @setup exit @exit In the above assembly language program, we first use the MOV instruction to initialize RO at O and R1 at 10. The ADD instruction computes the sum of RO and R1 (the second and third arguments) and places the result into RO (the first argument); this corresponds to the total += i; line of the equivalent C program. Note the use of the label at the beginning of the ADD instruction. The label is simply the relative memory address of where that instruction is when the assembler loads it into memory. The subsequent SUBS instruction decreases R1 by 1. To understand the next instruction, we need to understand that in addition to the…Cover C++ to RISC-V int fib(int n) { if(n <=1) return n; else return fib(n-1) + fib(n-2); } int main() { int n = 4; int ret = fib(n); return 0; }Implement the following C code (or python code) in MIPS assembly. Please your understandings in comments for MIPS code line by line C code: int fib(int n){ if (n==0) return 0; else if (n == 1) return 1; else return 2; } python code: def fib(n): if (n==0): return 0 elif (n == 1): return 1 else return 2translate the following c program into pep/9 assembly languagereq code in javaPlease translate this to assembly from C language. Comment what each line of the code in assembly is doing. Please do not reference disassembly tools or compilers. Simply translate this to ARM assembly. If you are unsure please pass on this question. Thank you void SVN_SEG(unsigned int n){ int i=0; uint32_t temp=0; SEG_CTL=1; for(i=0; i<4; i++){ temp |= (n&0xF)<<(i*8); n>>4; } temp |= 0x80808080; SEG_DATA = temp; }Convert this following C++ code below to easy68k assembly language: int sum = 0; int c =1; for (unsigned short i = 0; i <= 10; i++) { if (c == 1 ) { sum += i; c = 0; } else { c = 1; } }Translate the following C program to Pep/9 assembly language. #include int inpNum, sum, count, min; int main() { sum = 0; count = 0; min = 32767; printf("? "); scanf("%d", &inpNum); while (inpNum != 0 ) { sum += inpNum; count++; if (inpNum < min) { min = inpNum; } printf("? "); scanf("%d", &inpNum); } // end while printf("Sum printf("Count printf("Min } // end of main = = %d\n", sum); = %d\n", count); %d\n", min);Convert the C function below to MIPS assembly language. Make sure you follow the MIPS calling conventions. unsigned int sum(unsigned int n) { if (n == 0) return %; else return n+ sum(n-1); %3D%3DMIPS Programming Assignment Part I Rewrite C statements int i = 11; int j = 10; int A[] = { 0x11, 0x22, 0x33 }; int B[] = { 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 }; B[ 8 ] = A[ i - j ]; in MIPS assembly. Assume that addresses of variables i, j, A, and B are loaded into the registers $s3, $s4, $s6, and $s7, respectively: .data i: .word 11 j: .word 10 A: .word 0x11, 0x22, 0x33 B: .word 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 .text la $s3, i # load address of i la $s4, j # load address of j la $s6, A # load address of A la $s7, B # load address of B When you finished programming, add a comment at the end of your code which specifies what value is assigned to the location of B[8] after the program executes. Part IIWrite MIPS Assembly program that allows the user to enter a string of text. Determine whether the entered string is a palindrome (a word or a phrase that reads the same backward as forward, like "kayak" and "level") and print the result on the screen.Write assembly code equivalent to the following C codeVoid myfunction(int *z , int x, int y ){int t = x;int b = y;*z= (t*b) +z +2;}SEE MORE QUESTIONS