E. Estimate the required air flow rate for the new activated sludge plant at Camp Verde Problems 23-3 — 23-823-11, and 23-14 B). Use the following assumptions in preparing the estimate: Clean water correction, a 0.70 . Salinity correction, ẞ= 0.95 . Fouling factor = 0.8 Summer wastewater temperature 22°C • Atmospheric pressure 101.325 kPa .Elevation 2,135 m Depth of aerator = 4.5 m Operating DO = 2.0 mg/L Percent oxygen leaving aeration tank - 19% Manufacturer's SOTR = 650 kg/d • Manufacturer's air flow rate at standard conditions 20 m3/d aerator 23-3. The town of Camp Verde has been directed to upgrade its primary WWTP to a secondary plant that can meet an effluent standard of 25.0 mg/L BOD5 and 30 mg/L suspended solids. They have se- lected a completely mixed activated sludge system for the upgrade. The existing primary treatment plant has a flow rate of 2,506 m³/d. The effluent from the primary tank has a BOD5 of 240 mg/L. Using the following assumptions, estimate the required volume of the aeration tank: 23-8. Determine the return sludge concentration (X) that results in the maximum return sludge flow rate for Camp Verde's proposed activated sludge plant described in Problem 23-3. Also estimate the mass flow rate of sludge wasting. Use the following assumption: MLVSS fraction of MLSS = 0.70
E. Estimate the required air flow rate for the new activated sludge plant at Camp Verde Problems 23-3 — 23-823-11, and 23-14 B). Use the following assumptions in preparing the estimate: Clean water correction, a 0.70 . Salinity correction, ẞ= 0.95 . Fouling factor = 0.8 Summer wastewater temperature 22°C • Atmospheric pressure 101.325 kPa .Elevation 2,135 m Depth of aerator = 4.5 m Operating DO = 2.0 mg/L Percent oxygen leaving aeration tank - 19% Manufacturer's SOTR = 650 kg/d • Manufacturer's air flow rate at standard conditions 20 m3/d aerator 23-3. The town of Camp Verde has been directed to upgrade its primary WWTP to a secondary plant that can meet an effluent standard of 25.0 mg/L BOD5 and 30 mg/L suspended solids. They have se- lected a completely mixed activated sludge system for the upgrade. The existing primary treatment plant has a flow rate of 2,506 m³/d. The effluent from the primary tank has a BOD5 of 240 mg/L. Using the following assumptions, estimate the required volume of the aeration tank: 23-8. Determine the return sludge concentration (X) that results in the maximum return sludge flow rate for Camp Verde's proposed activated sludge plant described in Problem 23-3. Also estimate the mass flow rate of sludge wasting. Use the following assumption: MLVSS fraction of MLSS = 0.70
Solid Waste Engineering
3rd Edition
ISBN:9781305635203
Author:Worrell, William A.
Publisher:Worrell, William A.
Chapter8: Landfills
Section: Chapter Questions
Problem 8.10P
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Transcribed Image Text:E. Estimate the required air flow rate for the new activated sludge plant at Camp Verde Problems 23-3 —
23-823-11, and 23-14 B). Use the following assumptions in preparing the estimate:
Clean water correction, a 0.70
. Salinity correction, ẞ= 0.95
. Fouling factor = 0.8
Summer wastewater temperature 22°C
• Atmospheric pressure 101.325 kPa
.Elevation 2,135 m
Depth of aerator = 4.5 m
Operating DO = 2.0 mg/L
Percent oxygen leaving aeration tank - 19%
Manufacturer's SOTR = 650 kg/d
• Manufacturer's air flow rate at standard conditions 20 m3/d aerator
23-3. The town of Camp Verde has been directed to upgrade its primary WWTP to a secondary plant
that can meet an effluent standard of 25.0 mg/L BOD5 and 30 mg/L suspended solids. They have se-
lected a completely mixed activated sludge system for the upgrade. The existing primary treatment
plant has a flow rate of 2,506 m³/d. The effluent from the primary tank has a BOD5 of 240 mg/L. Using
the following assumptions, estimate the required volume of the aeration tank:
23-8. Determine the return sludge concentration (X) that results in the maximum return sludge flow
rate for Camp Verde's proposed activated sludge plant described in Problem 23-3. Also estimate the
mass flow rate of sludge wasting. Use the following assumption:
MLVSS fraction of MLSS = 0.70
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