Procedure: 1- Define your Cartesian system. 2- Identify the structure's supports and the type of structure (2D) or 3D 3- If the structure has more than one element dismember the structure and draw free body diagram (show all actions and reactions) on each element independently. Tip: Pulley is a member Rope is not an element because it is flexible, but it shows the force (substitute it with a force) If the Structure has one element draw free body diagram for the element. Tips to show forces on the free body diagram: 3.1- Determine the type of the supports 3.2- Show the unknown support reactions with any assumed direction, BUT you cannot change the assumed force direction once you decide. 3.3- In a common joint, you can decide on the force direction in one element, however, in the other one you need to follow the Newton's 3rd law and show the opposite direction. 3.4- If you have multiple action forces in the system, find force components for each force independently. Use Sin/Cos/Tan functions to find force components in two perpendicular directions. 3.5- Add forces in each direction since they are parallel forces Rx=ΣFx Ry=ΣFy Rz=ΣFz The bracket BCD is hinged at C and attached to a control cable at B. For the loading shown, determine (a) the tension in the cable, (b) the reaction at C.. 724 last 2 student's ID#+100 last 3 student's ID# N 24 N B C ΤΑ D 200 N last 1 student's ID#+3 (meters) 4
Procedure: 1- Define your Cartesian system. 2- Identify the structure's supports and the type of structure (2D) or 3D 3- If the structure has more than one element dismember the structure and draw free body diagram (show all actions and reactions) on each element independently. Tip: Pulley is a member Rope is not an element because it is flexible, but it shows the force (substitute it with a force) If the Structure has one element draw free body diagram for the element. Tips to show forces on the free body diagram: 3.1- Determine the type of the supports 3.2- Show the unknown support reactions with any assumed direction, BUT you cannot change the assumed force direction once you decide. 3.3- In a common joint, you can decide on the force direction in one element, however, in the other one you need to follow the Newton's 3rd law and show the opposite direction. 3.4- If you have multiple action forces in the system, find force components for each force independently. Use Sin/Cos/Tan functions to find force components in two perpendicular directions. 3.5- Add forces in each direction since they are parallel forces Rx=ΣFx Ry=ΣFy Rz=ΣFz The bracket BCD is hinged at C and attached to a control cable at B. For the loading shown, determine (a) the tension in the cable, (b) the reaction at C.. 724 last 2 student's ID#+100 last 3 student's ID# N 24 N B C ΤΑ D 200 N last 1 student's ID#+3 (meters) 4
Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter1: Introduction
Section: Chapter Questions
Problem 3CQ
Related questions
Question
Transcribed Image Text:Procedure:
1- Define your Cartesian system.
2- Identify the structure's supports and the type
of structure (2D) or 3D
3- If the structure has more than one element
dismember the structure and draw free body
diagram (show all actions and reactions) on
each element independently.
Tip: Pulley is a member
Rope is not an element because it is flexible,
but it shows the force (substitute it with a force)
If the Structure has one element draw free body
diagram for the element.
Tips to show forces on the free body diagram:
3.1- Determine the type of the supports
3.2- Show the unknown support reactions with
any assumed direction, BUT you cannot change
the assumed force direction once you decide.
3.3- In a common joint, you can decide on the
force direction in one element, however, in the
other one you need to follow the Newton's 3rd
law and show the opposite direction.
3.4- If you have multiple action forces in the
system, find force components for each force
independently.
Use Sin/Cos/Tan functions to find force
components in two perpendicular directions.
3.5- Add forces in each direction since they are
parallel forces
Rx=ΣFx
Ry=ΣFy
Rz=ΣFz
Transcribed Image Text:The bracket BCD is hinged at C and attached to a control cable at B. For the loading shown, determine (a) the tension in the
cable, (b) the reaction at C..
724
last 2 student's ID#+100
last 3 student's ID# N
24 N
B
C
ΤΑ
D
200 N
last 1 student's ID#+3 (meters)
4
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