The following data was reported on total Fe for four types of iron formation (1 = carbonate, 2 = 1: 21.0 28.1 27.8 27.0 28.5 25.2 25.3 27.1 20.5 31.1 2: 26.2 24.0 26.2 20.2 24.3 34.0 17.1 26.8 23.7 25.3 3: 30.3 34.0 27.5 29.4 28.2 26.2 29.9 29.5 30.0 36.5 4: 37.2 44.2 34.1 30.3 31.8 33.1 34.1 32.9 36.3 25.8 silicate, 3 = magnetite, 4 = USE SALT Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses. O Ho H₁ =μ₂ = 3 = μ4 H: at least two μ's are unequal # O Ho: H1 H2 H3 H4 Ha: at least two μ's are equal # # O Ho: H1 H2 H3 H4 Ha all four μ's are equal O Ho H1 H2 H3 = 4 H: all four μ's are unequal Summarize the results in an ANOVA table. (Round your answers two decimal places.) Sum of Mean Source df Squares Squares f Treatments Error Total Give the test statistic. (Round your answer to two decimal places.) f = What can be said about the P-value for the test? OP-value>0.100 0.050 < P-value < 0.100 0.010 < P-value < 0.050 0.001 < P-value < 0.010 ○ P-value < 0.001 State the conclusion in the problem context. ◇ Reject Ho. There is insufficient evidence to conclude that the total Fe differs for the four formations. Reject Ho. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations. Fail to reject Ho. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations. ◇ Fail to reject Ho. There is insufficient evidence to conclude that the total Fe differs for the four formations. hematite).

Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter11: Fracture And Fatigue
Section: Chapter Questions
Problem 6ETSQ
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The following data was reported on total Fe for four types of iron formation (1 =
carbonate, 2 =
1: 21.0 28.1 27.8 27.0 28.5 25.2 25.3 27.1 20.5 31.1
2: 26.2 24.0 26.2 20.2 24.3 34.0 17.1 26.8 23.7 25.3
3: 30.3 34.0 27.5 29.4 28.2 26.2 29.9 29.5 30.0 36.5
4: 37.2 44.2 34.1 30.3 31.8 33.1 34.1 32.9 36.3 25.8
silicate, 3 = magnetite, 4 =
USE SALT
Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses.
O Ho H₁ =μ₂ = 3 = μ4
H: at least two μ's are unequal
#
O Ho: H1 H2 H3 H4
Ha: at least two μ's are equal
#
#
O Ho: H1 H2 H3 H4
Ha all four μ's are equal
O Ho H1 H2 H3 = 4
H: all four μ's are unequal
Summarize the results in an ANOVA table. (Round your answers two decimal places.)
Sum of Mean
Source
df
Squares Squares
f
Treatments
Error
Total
Give the test statistic. (Round your answer to two decimal places.)
f =
What can be said about the P-value for the test?
OP-value>0.100
0.050 < P-value < 0.100
0.010 < P-value < 0.050
0.001 < P-value < 0.010
○ P-value < 0.001
State the conclusion in the problem context.
◇ Reject Ho. There is insufficient evidence to conclude that the total Fe differs for the four formations.
Reject Ho. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations.
Fail to reject Ho. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations.
◇ Fail to reject Ho. There is insufficient evidence to conclude that the total Fe differs for the four formations.
hematite).
Transcribed Image Text:The following data was reported on total Fe for four types of iron formation (1 = carbonate, 2 = 1: 21.0 28.1 27.8 27.0 28.5 25.2 25.3 27.1 20.5 31.1 2: 26.2 24.0 26.2 20.2 24.3 34.0 17.1 26.8 23.7 25.3 3: 30.3 34.0 27.5 29.4 28.2 26.2 29.9 29.5 30.0 36.5 4: 37.2 44.2 34.1 30.3 31.8 33.1 34.1 32.9 36.3 25.8 silicate, 3 = magnetite, 4 = USE SALT Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses. O Ho H₁ =μ₂ = 3 = μ4 H: at least two μ's are unequal # O Ho: H1 H2 H3 H4 Ha: at least two μ's are equal # # O Ho: H1 H2 H3 H4 Ha all four μ's are equal O Ho H1 H2 H3 = 4 H: all four μ's are unequal Summarize the results in an ANOVA table. (Round your answers two decimal places.) Sum of Mean Source df Squares Squares f Treatments Error Total Give the test statistic. (Round your answer to two decimal places.) f = What can be said about the P-value for the test? OP-value>0.100 0.050 < P-value < 0.100 0.010 < P-value < 0.050 0.001 < P-value < 0.010 ○ P-value < 0.001 State the conclusion in the problem context. ◇ Reject Ho. There is insufficient evidence to conclude that the total Fe differs for the four formations. Reject Ho. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations. Fail to reject Ho. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations. ◇ Fail to reject Ho. There is insufficient evidence to conclude that the total Fe differs for the four formations. hematite).
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