Dilution Experiment Test tube Starch concentration (/mL) Dilution factor Observation 1 500 1:10 Dark blue 2 50 1:100 Light blue 3 5 1:1000 Light purple 4 0.5 1:10000 Yellow 5 0.05 1:100000 Light yellow   Observation: 1 has the highest concentration of starch and the following sample which are test tube 2, 3, 4 and 5 have lighter in colour which are light blue, purple, yellow and light yellow in colour respectively. Question: Discuss about the dilution experiment. Explain about the change in colour, the structure of the starch. Explain about iodine also. Calculation below (starch concentration).

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
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Dilution Experiment

Test tube

Starch concentration (/mL)

Dilution factor

Observation

1

500

1:10

Dark blue

2

50

1:100

Light blue

3

5

1:1000

Light purple

4

0.5

1:10000

Yellow

5

0.05

1:100000

Light yellow

 

Observation: 1 has the highest concentration of starch and the following sample which are test tube 2, 3, 4 and 5 have lighter in colour which are light blue, purple, yellow and light yellow in colour respectively.

Question: Discuss about the dilution experiment. Explain about the change in colour, the structure of the starch. Explain about iodine also. Calculation below (starch concentration).

Test tube 1:
(Weight / Volume) x 100 % = 0.5%
(Weight/ 1ml) x 100 % = 0.5%
Weight = 0.005g = 5mg = 500µg
X= 500µg/ml = starch concentration for test tube A
Test tube 2:
Test tube 4:
M1V1=M2V2
M1V1=M2V2
(500)(1)= M2 (10)
(5)(1)= M2 (10)
M2= 50µg/ml
M2= 0.5µg/ml
Test tube 3:
Test tube 5:
M1V1=M2V2
M1V1=M2V2
(50)(1)= M2 (10)
(0.5)(1)= M2 (10)
M2-5µg/ml
M2=0.05ug/ml
Transcribed Image Text:Test tube 1: (Weight / Volume) x 100 % = 0.5% (Weight/ 1ml) x 100 % = 0.5% Weight = 0.005g = 5mg = 500µg X= 500µg/ml = starch concentration for test tube A Test tube 2: Test tube 4: M1V1=M2V2 M1V1=M2V2 (500)(1)= M2 (10) (5)(1)= M2 (10) M2= 50µg/ml M2= 0.5µg/ml Test tube 3: Test tube 5: M1V1=M2V2 M1V1=M2V2 (50)(1)= M2 (10) (0.5)(1)= M2 (10) M2-5µg/ml M2=0.05ug/ml
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