I need help with my homework this question is very confusingHow long would it take for a solution made by diluting 2.5 ml of #1 with 7.5 ml of H2O to react with 10 ml of #2? **Procedure A: Effect of Concentration**1. Fill each buret on the stand with the solution it is marked for.2. Deliver exactly 10 ml of solution #1 into a clean, dry test tube from the buret.3. Deliver exactly 10 ml of solution #2 into a separate clean, dry test tube.3. Prepare the stopwatch, then mix solutions 1 and 2 by pouring back and forth between the test tubes three times. Begin timing the reaction as soon as you start mixing. Stop timing as soon as a color change occurs. You may need to practice this a few times before proceeding.4. Repeat the procedure using successive dilutions of solution #1 as per the data chart on the report sheet.5. Calculate the reaction rate by using 100 divided by the time in seconds.7. On graph paper, plot a graph of your reaction rates versus concentration. Use the vertical scale or Y-axis to represent the reaction rate, and the horizontal scale or X-axis to represent milliliters of solution #1 (KIO₃).**Explanation of Graph**Create a graph with the Y-axis representing the reaction rate and the X-axis showing the volume of solution #1 (potassium iodate, KIO₃) in milliliters. This graph will help visualize how different concentrations affect reaction rates. **Table of KIO₃ and H₂O Reaction Rates with Starch**| Trial | KIO₃ + H₂O (Test Tube 1) | Starch (Test Tube 2) | Time (sec) | Rate 100/t (s⁻¹) ||-------|-------------------------|---------------------|-----------|------------------|| 1 | 10 ml + 0 ml | 10 ml | 18 | 5.5 s⁻¹ || 2 | 7 ml + 3 ml | 10 ml | 27 | 3.7 s⁻¹ || 3 | 5 ml + 5 ml | 10 ml | 32 | 3.1 s⁻¹ || 4 | 2 ml + 8 ml | 10 ml | 68 | 1.5 s⁻¹ |**Description:**- **KIO₃ + H₂O (Test Tube 1)**: Mixture of potassium iodate and water in varying proportions.- **Starch (Test Tube 2)**: Constant 10 ml of starch solution is used in each trial.- **Time (sec)**: The time taken for the reaction to complete.- **Rate 100/t (s⁻¹)**: Calculated rate of the reaction, using the formula 100 divided by time in seconds. This table displays a series of experimental trials measuring the effect of varying concentrations of KIO₃ and H₂O on the reaction time with starch.

Concentration of carbohydrate in a solution is the moles of carbohydrate present in a specified volume of solution. Different techniques are applied to compare the effect of concentration on reaction rate of reaction.This can be calculated using different quantitative test which is determined by reaction time in which carbohydrate present in the solution reacts with reagent and gives color and plotting graph for the same will give amount of carbohydrate as more carbohydrate will give a faster reaction as more quantity is available to react with the reagent to provide color. In the given question, given set of data will give graph as follows: According to this graph 7.5 ml of KClO3, if 7.5 ml is plotted against reaction rate, it will yield reaction rate of 4 s-1. The reaction rate of limit is 100/t=4 sec-1. Thus time can be calculated as: rate of recation=100t=4t=25 seconds Hence, it would take 25 seconds for a solution made by diluting 2.5 ml of #1 with 7.5 ml of H2O to react with 10 ml of #2.