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Consider the reaction 2X,Y2 + Z2 = 2X2Y2Z which has a rate law of rate = k[X2Y2][Z2] Select a possible mechanism for the reaction. View Available Hint(s) (slow) Step 2: X2Y2 +Z→X2Y2Z (fast) X2Y2 + Z→X2Y2Z (fast) Step 1: Z2→Z+Z A Step 3: Step 1: X2Y2 + Z2→X2Y2Z+Z (slow) Step 2: X2Y2 + Z→X2Y2Z (fast) Step 1: X2Y2 + Z2→X2Y2Z2 (slow) Step 2: X2Y2Z2→X2Y2Z+Z_(fast) Step 1: 2X2Y2= X4Y4 (fast) Step 2: X4Y4 + Z2→2X2Y½Z_ (slow) E Step 1: 2X2Y2+ Z2→2X2Y2 (slow)

Consider the reaction 2X,Y2 + Z2 = 2X2Y2Z which has a rate law of rate = k[X2Y2][Z2] Select a possible mechanism for the reaction. View Available Hint(s) (slow) Step 2: X2Y2 +Z→X2Y2Z (fast) X2Y2 + Z→X2Y2Z (fast) Step 1: Z2→Z+Z A Step 3: Step 1: X2Y2 + Z2→X2Y2Z+Z (slow) Step 2: X2Y2 + Z→X2Y2Z (fast) Step 1: X2Y2 + Z2→X2Y2Z2 (slow) Step 2: X2Y2Z2→X2Y2Z+Z_(fast) Step 1: 2X2Y2= X4Y4 (fast) Step 2: X4Y4 + Z2→2X2Y½Z_ (slow) E Step 1: 2X2Y2+ Z2→2X2Y2 (slow)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Consider the reaction 2X2Y2 + Z2 = 2X,Y½Z which has a rate law of rate = k[X2Y2][Z2] Select a possible mechanism for the reaction. > View Available Hint(s) (slow) Step 2: X2Y2 +Z→X,Y2Z (fast) X2Y2 + Z→X2Y2Z (fast) Step 1: Z2→Z+Z A Step 3: Step 1: X,Y2 + Z2→X2Y2Z+ Z (slow) В Step 2: X2Y2 + Z→X2 Y½Z (fast) Step 1: X2Y2 + Z2→X2Y2Z2 (slow) Step 2: X2Y2Z2→X2Y2Z+Z (fast) Step 1: 2X,Y2 =X4Y4 (fast) Step 2: X4Y4 + Z2→2X2Y2Z (slow) O E Step 1: 2X,Y2+Z2→2X2Y2 (slow)
Transcribed Image Text:Consider the reaction 2X2Y2 + Z2 = 2X,Y½Z which has a rate law of rate = k[X2Y2][Z2] Select a possible mechanism for the reaction. > View Available Hint(s) (slow) Step 2: X2Y2 +Z→X,Y2Z (fast) X2Y2 + Z→X2Y2Z (fast) Step 1: Z2→Z+Z A Step 3: Step 1: X,Y2 + Z2→X2Y2Z+ Z (slow) В Step 2: X2Y2 + Z→X2 Y½Z (fast) Step 1: X2Y2 + Z2→X2Y2Z2 (slow) Step 2: X2Y2Z2→X2Y2Z+Z (fast) Step 1: 2X,Y2 =X4Y4 (fast) Step 2: X4Y4 + Z2→2X2Y2Z (slow) O E Step 1: 2X,Y2+Z2→2X2Y2 (slow)
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