You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrOs (aq) + 5Br (aq) + 6H* (aq) →3Br₂ () + 3H₂O (1) Trial Initial rate [BrOs] (mol/L) 0.10 0.20 0.10 0.10 a. Based on the above data what is the rate law expression? 1 2 3 4 [H*] (mol/L) 0.10 0.10 0.20 0.10 [Br] (mol/L) 0.10 0.10 0.10 0.20 (mol/L-s) 8.0 16 16 32
You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrOs (aq) + 5Br (aq) + 6H* (aq) →3Br₂ () + 3H₂O (1) Trial Initial rate [BrOs] (mol/L) 0.10 0.20 0.10 0.10 a. Based on the above data what is the rate law expression? 1 2 3 4 [H*] (mol/L) 0.10 0.10 0.20 0.10 [Br] (mol/L) 0.10 0.10 0.10 0.20 (mol/L-s) 8.0 16 16 32
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:b. Solve for the value of k (make sure to include proper units)
![You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure
the initial reaction rate and the starting concentrations of the reactions for 4 trials.
BrO3 (aq) + 5Br (aq) + 6H+ (aq) → 3Br₂ (1) + 3H₂O (1)
Trial
a.
[BrO3]
(mol/L)
0.10
0.20
0.10
0.10
Based on the above data what is the rate law expression?
1
2
[H]
[Br] Initial rate
(mol/L)| (mol/L)| (mol/L.s)
0.10
0.10
8.0
0.10
0.10
0.20
0.10
0.10
0.20
3
4
16
16
32](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F562be926-3944-4e0d-b74b-e105fbdc55fe%2Fc0a9cf8a-bd42-4473-9854-c134baa8609b%2Fx2pbitk_processed.png&w=3840&q=75)
Transcribed Image Text:You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure
the initial reaction rate and the starting concentrations of the reactions for 4 trials.
BrO3 (aq) + 5Br (aq) + 6H+ (aq) → 3Br₂ (1) + 3H₂O (1)
Trial
a.
[BrO3]
(mol/L)
0.10
0.20
0.10
0.10
Based on the above data what is the rate law expression?
1
2
[H]
[Br] Initial rate
(mol/L)| (mol/L)| (mol/L.s)
0.10
0.10
8.0
0.10
0.10
0.20
0.10
0.10
0.20
3
4
16
16
32
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