This Reaction carried out room temperature (2.5°C) and the rate constant is determined to be 7.4 x 10-4 M² sec¹ (the exponent M is x to avoid the earlier giving away. parts of the Question.) If the activation energy for this reaction is 52.9 kj/mol, then the rate constant at (35°C) would be ☆ ☆
This Reaction carried out room temperature (2.5°C) and the rate constant is determined to be 7.4 x 10-4 M² sec¹ (the exponent M is x to avoid the earlier giving away. parts of the Question.) If the activation energy for this reaction is 52.9 kj/mol, then the rate constant at (35°C) would be ☆ ☆
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Just the last one(:
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Question 4
Given the following mechanism:
H₂O₂ (aq) + I (aq) → H₂O (1) + OI (aq) (slow)
H₂O₂ (aq) + OI (aq) → H₂O (1) + O₂ (9) + I- (aq) (fast)
The rate law consistent with this mechanism is [Select]
The intermediate in this reaction is [Select]
A plot of [Select]
and the catalyst is [Select]
for this reaction would be linear.
This reaction is carried out room temperature (25 °C) and the rate constant is determined to be 7.4 x 104 M*sec (the exponer
Its cut off.... below is
what is says
#
giving away
This Reaction carried out room temperature (2.5°C) and the rate constant is
determined to be 7.4 x 10-4 MX sec-¹ (the exponent M is x to avoid
parts of the Question.) If the activation energy for this reaction
is 52.9 kj/mol, then the rate constant at (35°C) would
be
the earlier](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbae483e7-f3a4-4a9a-ba35-bb8b04de3604%2F62a32c20-d9f0-4ac6-b1c9-6e998da42367%2Fio0v78_processed.jpeg&w=3840&q=75)
Transcribed Image Text:D
Question 4
Given the following mechanism:
H₂O₂ (aq) + I (aq) → H₂O (1) + OI (aq) (slow)
H₂O₂ (aq) + OI (aq) → H₂O (1) + O₂ (9) + I- (aq) (fast)
The rate law consistent with this mechanism is [Select]
The intermediate in this reaction is [Select]
A plot of [Select]
and the catalyst is [Select]
for this reaction would be linear.
This reaction is carried out room temperature (25 °C) and the rate constant is determined to be 7.4 x 104 M*sec (the exponer
Its cut off.... below is
what is says
#
giving away
This Reaction carried out room temperature (2.5°C) and the rate constant is
determined to be 7.4 x 10-4 MX sec-¹ (the exponent M is x to avoid
parts of the Question.) If the activation energy for this reaction
is 52.9 kj/mol, then the rate constant at (35°C) would
be
the earlier
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