**Beam Analysis: Shear Force and Moment Calculation****Problem Statement:**Consider the beam shown in Figure 1. Suppose that the distributed load is \( w = 9 \ \text{kips/ft} \). Follow the sign convention.**Figure Description:**- The figure shows a simply supported beam labeled \( A \) and \( B \) with a span of 12 feet, divided into two 6-foot segments.- A triangular distributed load acts from point \( A \) to point \( C \).- The peak of the triangle is at point \( C \), which is at the midpoint of the beam.**Part A:**- Task: Determine the internal shear force acting at point \( C \).- Instructions: Express your answer to three significant figures and include the appropriate units.- Input Field: \( V_C = \ \text{Value} \ \text{Units} \)- Message: Incorrect; Try Again; 3 attempts remaining.**Part B:**- Task: Determine the internal moment acting at point \( C \).- Instructions: Express your answer to three significant figures and include the appropriate units.- Input Field: \( M_C = \ \text{Value} \ \text{Units} \)- Message: Incorrect; Try Again; 2 attempts remaining.**Note:** Ensure calculations adhere to specified precision and unit conventions.

Given : - A beam is given with hinge support at point A and roller support at point B Uniformly distributed load (w) = 9 kip/ft To determine :- a) The internal shear force acting at point C b) The internal moment acting at point C Free body diagram of the beam Let the support reaction at A be RA, HA Let the support reaction at B be RB So, Support reaction can be calculated by applying quation of equilibrium ΣFX=0HA=0ΣFY=0RA+RB=12×w×6RA+RB=12×9×6RA+RB=27 ...(1)ΣMA=0RB×12-12×6×w×23×6=0RB×12-12×6×9×23×6=0RB×12= 108RB= 9 kipsPutting the value of RB in equation (1)RA+9=27 RA=27-9RA=18 kipsNow, Free body diagram at C a) The shear force at point C will be ΣFY=0VC-RB=0VC=RBVC=9 kips b) The moment about point C will be Taking moment about CMC-RB×6=0MC-9×6=0MC= 54 kip/ft

Engineering

Civil Engineering

Consider the beam shown in (Figure 1). Suppose that the distributed load is w = 9 kip/ft. Follow the sign convention. Part A Determine the internal shear force acting at point C. Express your answer to three significant figures and include the appropriate units. ? Ve= Value Units Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Figure 1 of 1 Part B Determine the internal moment acting at point C. Express your answer to three significant figures and include the appropriate units. ? Mc = Value Units 6 ft 6 ft Submit Previous Answers Request Answer

Consider the beam shown in (Figure 1). Suppose that the distributed load is w = 9 kip/ft. Follow the sign convention. Part A Determine the internal shear force acting at point C. Express your answer to three significant figures and include the appropriate units. ? Ve= Value Units Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Figure 1 of 1 Part B Determine the internal moment acting at point C. Express your answer to three significant figures and include the appropriate units. ? Mc = Value Units 6 ft 6 ft Submit Previous Answers Request Answer

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

**Beam Analysis: Shear Force and Moment Calculation**

**Problem Statement:**
Consider the beam shown in Figure 1. Suppose that the distributed load is \( w = 9 \ \text{kips/ft} \). Follow the sign convention.

**Figure Description:**
- The figure shows a simply supported beam labeled \( A \) and \( B \) with a span of 12 feet, divided into two 6-foot segments.
- A triangular distributed load acts from point \( A \) to point \( C \).
- The peak of the triangle is at point \( C \), which is at the midpoint of the beam.

**Part A:**
- Task: Determine the internal shear force acting at point \( C \).
- Instructions: Express your answer to three significant figures and include the appropriate units.
- Input Field: \( V_C = \ \text{Value} \ \text{Units} \)
- Message: Incorrect; Try Again; 3 attempts remaining.

**Part B:**
- Task: Determine the internal moment acting at point \( C \).
- Instructions: Express your answer to three significant figures and include the appropriate units.
- Input Field: \( M_C = \ \text{Value} \ \text{Units} \)
- Message: Incorrect; Try Again; 2 attempts remaining.

**Note:** Ensure calculations adhere to specified precision and unit conventions.

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