In the position shown in (Figure 1), cords ABAB and CAD can each support a maximum tension of 80 lb. Suppose that γ = 19 and θ <90∘ What is the angle θ for equilibrium?

Q: A wooden bar beam arrangement is shown in the figure. The beam is formed by nailing wooden bar and…

A: Given,B = 200 mm H = 360 mm t = 20 mm F = 250 NV = 3.2 kN or 3200 N

Q: The beam shown in the figure below is subject to a moment of M = 10 kN.m as illustrated. Calculate…

A:

Q: ▾ Part A 4.5 ft- -4.5 ft- 3 ft- Determine the absolute maximum bending stress in the beam, assuming…

A: P= 16 kips

Q: A pin-jointed plane truss shown in Figure Q1 is supported by a roller at point A and pinned at point…

A: To find force in all members of the truss

Q: The gusset plate is subjected to the forces of three members as shown in (Eigure 1). The forces are…

A: Consider vertical force equilibrium9 - 6sin - Tsin = 09 - 6* - Tsin = 0Tsin =  5.4 ...equation…

Q: 2. As shown in the figure, two aluminum rods AB and BC, hinged to rigid supports, are pinned…

A:

Q: 9. The rigid bar ABC shown in the figure is hinged at A and supported by a steel rod at B. Determine…

A: Given Length = 4 ft Area = 0.5 sq.in Elastic modulus =29(10)6 psi Required = value of P satisfying…

Q: Pin G B (b) (a)

A:

Q: Consider the beam in the figure below. Take P = 20 kN (Figure 1) Figure 60 kN-m A -2 m-1 m-1 m- -2m-…

A: A beam,Free body diagram of given beam:-

Q: A steel beam (E = 208GPa) has square cross-section (edge = 40mm) and is constrained and loaded as in…

A:

Q: The steel tie-bar shown in the figure has been designed to carry a tension force of 76 kN when…

A:

Q: A double tee cross section is used for the beam shown below. Assume the following lengths and loads:…

A: Moment of inertia (Iz) = 110 in.4 Determine the maximum tensile bending stress.

Q: 1

A: Step 1: Step 2:

Q: A horizontal bar of negligible mass is hinged at A and assumed to be rigid. It is supported by an…

A:

Q: Consider the stepped bar made with a linear elastic material and subjected to an axial load of1 kN,…

A: Given- Stepped bar- Axial load P=1 KN, Cross sectional areas A1=100 mm2, A2=60 mm2, Young's modulus-…

Q: A SOLID ALUMINUM SHAFT 2 INCH DIAMETER IS SUBJECTED TO TWO TORQUES AS SHOWN IN THE FIGURE. DETERMINE…

A: Given data: Diameter of shaft=2 inch Torque=T1=200 lb-ft T2=800 lb-ft It is asked to find maximum…

Q: The force in DB of the truss shown in below figure is W A 200 5 W tension O VW tension 5m 2 W…

A: A truss is given we need to find out force in member DB

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.