what is the maximum allowable force P applied at Point B if Callow = 200 MPa ? What is the corresponding displacement at 3 if E= 75 GPa? A B 3 Free body diagram Why are we ・using "R" ? fir 0.25 0.2P PR ZFO-FA+P+R=O Sp+&R=0 compatability 0.00003P+0.00004167R=0 R=-0.8P shouldn't this be-8.7199p? P where is the 0.ap coming from? -0.8P 0.8P 0.8P 0.2P 400 300 20 Reduced structure under actual load →P SB=(PL 750 20 201 Segment AB segment BC Coss-section dimensions -How do we get these values ? segment BC is critical O.2P (150) AE JAB 300/75X10³) = 0.6mm 250 K OR SR=RL) AB+(RL) P all dimensions in mm 20 P(750) Sp=(PALE )ABZ 300 (75×10³) =0.00003P where is the 300 from? AEJABAE = R(0.00003+0.0000083) =R(0.00004167) 0.8P 400 • How do we get this value? =√₁1= 200MPa allow P=100,000 N
what is the maximum allowable force P applied at Point B if Callow = 200 MPa ? What is the corresponding displacement at 3 if E= 75 GPa? A B 3 Free body diagram Why are we ・using "R" ? fir 0.25 0.2P PR ZFO-FA+P+R=O Sp+&R=0 compatability 0.00003P+0.00004167R=0 R=-0.8P shouldn't this be-8.7199p? P where is the 0.ap coming from? -0.8P 0.8P 0.8P 0.2P 400 300 20 Reduced structure under actual load →P SB=(PL 750 20 201 Segment AB segment BC Coss-section dimensions -How do we get these values ? segment BC is critical O.2P (150) AE JAB 300/75X10³) = 0.6mm 250 K OR SR=RL) AB+(RL) P all dimensions in mm 20 P(750) Sp=(PALE )ABZ 300 (75×10³) =0.00003P where is the 300 from? AEJABAE = R(0.00003+0.0000083) =R(0.00004167) 0.8P 400 • How do we get this value? =√₁1= 200MPa allow P=100,000 N
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please explain how they got these values along with the steps used to find them.
Transcribed Image Text:what is the maximum allowable
force P applied at Point B if Callow = 200 MPa ? What is
the corresponding displacement at Bif E= 75 GPa? B
P
3 Free body diagram
FA
Why are we
•ucing "R" ?
0.2P
0.2P
PR
x=O-FA+P+R=O
Sp⋅+&R=0 compatability
0.00003P+0.00004167R=0
R=-0.8P shouldn't this be - 8.7199p?
0.8P
P
where is the 0.ap coming from?
-0.8P
0.817
400
10
SB-
0.2P
300
20
10
Reduced structure under actual load
P=(PLEASZ
P
कमै
750.
720
Segment AB segment BC
Coss-section dimensions
tat
O.2P (150)
=
AE JAB 300/75X10³)
-How do we get these values?
20
+R SR=RL) + (RL)
segment BC
is critical
250
0.6mm
all dimensions in mm
20
P(750)
AE JABL 300(75x10³)
=0.00003P
0.8P
400
where is the
300
=R(0.00003+0.0000083)
=R(0.00004167)
from?
How do we get
this value?
T
• Ollow 200MPa
P=100,000 N
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