Problem 1: Load Distribution The diagram is to support a 100 mm thick concrete slab. 5.8 kPa of dead load and 2.1 kPa of live load will be overlaying on the slab. The following is the cross-section of the beams: AB, GH = 250mm X 450mm AG, BH = 250mm X 450mm CD, EF = 250mm X 550mm a) Self weight = (0.25x0.55x5.4) x 15 = 11.1375 kN-A Tributary area = 5.4x1.25+5.4x1.5 =14.85m^2 Self load = (14.85x0.1) x 15 B = 22.275KN Dead load =14.85x5.8 =86.13KkN Total dead load =A+B+C - 110 54 5.4m - - 3m 2.5m 3m Determine the following if the unit weight of concrete is 15 kN/m3 a. b. C. b) Live load Dead loads acting on beam EF. Live load acting on beam CD. Dead load acting on girder AG. = 14.85x2.1 = 32. 185 KN Total live load = 32.185 c) Self weight = (0.25x0.45x8.5) x 15 = 34.425 kN-A Tributary area = 2.7x8.5 = 22.95m^2 Self load = (22.95x0.1) x 15 = 34.425kN-B Dead load = 22.95x5.8 = 133.11 KN-C Total dead load = A + B + C =161.88 kN =I ald

Problem 1: Load Distribution The diagram is to support a 100 mm thick concrete slab. 5.8 kPa of dead load and 2.1 kPa of live load will be overlaying on the slab. The following is the cross-section of the beams: AB, GH = 250mm X 450mm AG, BH = 250mm X 450mm CD, EF = 250mm X 550mm a) Self weight = (0.25x0.55x5.4) x 15 = 11.1375 kN-A Tributary area = 5.4x1.25+5.4x1.5 =14.85m^2 Self load = (14.85x0.1) x 15 B = 22.275KN Dead load =14.85x5.8 =86.13KkN Total dead load =A+B+C - 110 54 5.4m - - 3m 2.5m 3m Determine the following if the unit weight of concrete is 15 kN/m3 a. b. C. b) Live load Dead loads acting on beam EF. Live load acting on beam CD. Dead load acting on girder AG. = 14.85x2.1 = 32. 185 KN Total live load = 32.185 c) Self weight = (0.25x0.45x8.5) x 15 = 34.425 kN-A Tributary area = 2.7x8.5 = 22.95m^2 Self load = (22.95x0.1) x 15 = 34.425kN-B Dead load = 22.95x5.8 = 133.11 KN-C Total dead load = A + B + C =161.88 kN =I ald

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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