Compare enthalpy KJ/Kg, humidity ratio and specific volume, m3/kg using psychrometric chart andcalculated values for a certain area having a temperature of 35°C, relative humidity of 70 percent andbarometric pressure of 101.3 kPa.Assume further:Saturation pressure at 35°C = 5.318 kPaSpecific heat of dry air = 1.006 kJ/kg-KEnthalpy of saturated steam at 34°C = 2563.6 kJ/kgGas constant of dry air = 287 J/kg-KGas constant of water vapor= 461.5 J/kg-K

Answered: Compare enthalpy KJ/Kg, humidity ratio…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What is the enthalpy of the air-vapor mixture at 65% relative humidity and 93.2°F when the barometric pressure is 14.7 psi? Compare your calculated enthalpy using ideal gas relations and psychrometric chart reading. show psychrometric chart.
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What is the change in the boiling point of water at 1000 C per Pa change under atmospheric pressure conditions? The molar enthalpy of vaporization is 40.69 kJ mol-1, the molar volume of liquid water is 0.019 x 10-3 m3 mol-1, and the molar volume of steam is 30.199 x 10-3m3 mol-1, all at 100.000 C and 1.01325 bar. (Hint: change in temperature per change in pressure, dT/dP).
One useful equation is the change of enthalpy of compressible liquid with constant specific heat is:hsub2 - hsub1 = c (Tsub2 - Tsub1 ) + V (Psub2 - Psub1)Where: Tsubn = temperature at state nPsubn = pressure at state nV = specific volume of liquidWater with enthalpy with Csubp = 4.187 kJ/kg-K and v= 1.00 x 10 to the -3rd power cu.m/kg has the following states: State 1: Tsub1 = 19 C Psub1 = 1.013 x 10 to the 5th power PaState 2: Tsub2 = 30 C Psub2 = 0.113 MpaWhat is the change in enthalpy from state 1 to state 2? 46 kPa/kg O 56 kJ/kg O 46 kJ/kg O 46 kN/kg
A closed container with constant volume insulated against heat is divided into two compartments by a steel curtain. Achamber contains 2 kg of water at 800 kPa pressure and 80 oC temperature. The other compartment isis empty (vacuum). Then the steel curtain is removed and the water fills the whole container. EndIn the equilibrium state, since the pressure of the water is 10 kPa, the final temperature of the water andCalculate the volume of the tank.
Use the tables of moist-air properties to find the enthalpy and specific volume for air at 125°F (51°C) if the humidity ratio is 0.040.
2
Give answer all questions with explanation
(c) An air water vapor mixture has a dry bulb temperature of 50 °C and absolute molal humidity 0.0386 kmole water vapor/ kmole dry air. Using the psychrometric chart determine the psychrometric properties of the mixture. The vapor pressure of water at 50 °C is 92.51 mmHg.
Air with a relative humidity of 95% and temperature of 35°C is pumped into a chamber filled with a non-reactive porous material. The material has a porosity of 0.6 and is initially completely dry. After 15 minutes, air leaving the bed has temperature of 40°C and relative humidity of 5%. Complete this sentence: The air leaving the bed has a higher temperature than when it entered because: The latent heat of water in the gas phase was released by condensation onto the porous material The latent heat of water in the porous medium was released into the gas phase by a phase change. The latent heat of water in the gas phase was absorbed by evaporation The porous material was hot and transferred its energy to the air O Condensing water reacted with the porous material exothermically (that is, the reaction made heat)
The value for T is 32, for P is 0.6, for V is 1.48
The molar heat capacities for solid, liquid, and gaseous molecular Cl₂ can be written in the following general form, where the coefficients a, b, c and d are given in the table below. Phase solid liquid gas T Range (in K) 15-172.12 172.12-239.0 > 239.0 Note: Cpº R = a +bT+cT² +dT³ a -1.545 7.689 3.812 b (in K-¹) 0.1502 0.005582 0.001220 c (in K-²) -0.001179 -1.954 x 10-5 - 4.856 x 10-7 d (in K-³) 3.441 x 10-6 Tfus = 172.12 K AfusH = 6.406 kJ/mol Tvap = 239.0 K AvapH = 20.40 kJ/mol (a) Use this data to find the entropy content (in J/K) for molecular chlorine at 200 K, if the absolute entropy at 15 K is 1.401 J/K. (b) What is the change in enthalpy, AH (in kJ), if one mole of Cl₂ is heated from 200 to 250 K?

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