One useful equation is the change of enthalpy of compressible liquid with constant specific heat is:hsub2 - hsub1 = c (Tsub2 - Tsub1 ) + V (Psub2 - Psub1)Where: Tsubn = temperature at state nPsubn = pressure at state nV = specific volume of liquidWater with enthalpy with Csubp = 4.187 kJ/kg-K and v = 1.00 x 10 to the-3rd power cu.m/kg has the following states: State 1: Tsub1 = 19 C Psub1 = 1.013 x 10 to the 5th power PaState 2: Tsub2 = 30 C Psub2 = 0.113 Mpa What is the change in enthalpy from state 1 to state 2? 46 kPa/kg 56 kJ/kg 46 kJ/kg O 46 kN/kg

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One useful equation is the change of enthalpy of compressible liquid with constant
specific heat is:hsub2 - hsub1 = c (Tsub2 - Tsub1 ) + V (Psub2 - Psub1)Where:
Tsubn = temperature at state nPsubn = pressure at state nV = specific volume of
liquidWater with enthalpy with Csubp = 4.187 kJ/kg-K and v= 1.00 x 10 to the -3rd
power cu.m/kg has the following states: State 1: Tsub1 = 19 C Psub1 = 1.013 x
10 to the 5th power PaState 2: Tsub2 = 30 C Psub2 = 0.113 MpaWhat is the
change in enthalpy from state 1 to state 2?
46 kPa/kg
O 56 kJ/kg
O 46 kJ/kg
O 46 kN/kg
Transcribed Image Text:One useful equation is the change of enthalpy of compressible liquid with constant specific heat is:hsub2 - hsub1 = c (Tsub2 - Tsub1 ) + V (Psub2 - Psub1)Where: Tsubn = temperature at state nPsubn = pressure at state nV = specific volume of liquidWater with enthalpy with Csubp = 4.187 kJ/kg-K and v= 1.00 x 10 to the -3rd power cu.m/kg has the following states: State 1: Tsub1 = 19 C Psub1 = 1.013 x 10 to the 5th power PaState 2: Tsub2 = 30 C Psub2 = 0.113 MpaWhat is the change in enthalpy from state 1 to state 2? 46 kPa/kg O 56 kJ/kg O 46 kJ/kg O 46 kN/kg
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