Calculate the power consumption and the steady discharge of water between the reservoirs in the pipeline system shown in Figure 4.1. The static lift of the system is 15 m and the pipeline has diameter of 300 mm and 500 m in length with a friction factor A = 0.004. Head losses in the system include friction loss and minor head losses totalling 10V²/2g. Assume the efficiency at the duty point is equal to 38%. LV² (Darcy-Weisbach: hf = A for turbulent flow in pipes; efficiency: n = D 2g pgQH, P Pump Characteristics Discharge (l/s) Total Head (m) 0 45 10 44 30 39.5 50 29 70 6

Calculate the power consumption and the steady discharge of water between the reservoirs in the pipeline system shown in Figure 4.1. The static lift of the system is 15 m and the pipeline has diameter of 300 mm and 500 m in length with a friction factor A = 0.004. Head losses in the system include friction loss and minor head losses totalling 10V²/2g. Assume the efficiency at the duty point is equal to 38%. LV² (Darcy-Weisbach: hf = A for turbulent flow in pipes; efficiency: n = D 2g pgQH, P Pump Characteristics Discharge (l/s) Total Head (m) 0 45 10 44 30 39.5 50 29 70 6

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A centrifugal pump is used to pump water between two reservoirs as shown in the bellow figure. The dimensions and minor loss coefficients are provided in the figure. The pump rotates at 1600 rpm, the water inters the impeller normal to the blades and exits at an angle of 45° from radial. The inlet radius is 5.5-in, at which the blade width is 7.09-in. The outlet radius is 8.66-in, at which the blade width is 6.7-in. The volume flow rate is 23-cfm. Assuming 100 percent efficiency, calculate the net head produced by this pump in cm of water column height, the required brake horsepower in W and calculate the pump capability to pump water to upper reservoir. Reservoir z3-2, = 22.0 ft (elevation difference) D = 1.20 in (pipe diameter) KL. entrance = 0.50 (pipe entrance) KL. valve I = 2.0 (valve 1) KL. valve 2 = 6.8 (valve 2) Reservoir Valve 2 KL elbow = 0.34 (each elbow-there are 3) KLe L = 124 ft (total pipe length) e =0.0011 in (pipe roughness) = 1.05 (pipe exit) exit Pump Valve 1
Please check attach file
A pipe carrying water tapers from 300 mm diameter to 150 mm diameter. Section l is 8 m and Section 2 is 3 m above the reference line. The pressure at section 1 is 2 MPa and at section 2 is 0.5 MPa, both are above atmospheric pressure. The discharge is 2.4 m3/min. Find i. The head loss between section 1 and 2 by using Bernoulli's equation ii. Difference of kinetic heads between section 1 and section 2 /// 7//// / ! // Q=2.4 m³/min 8 m 3 m Reference line P-2 Мра =300 mm P-0.5 Мра D=150 mm
Water is pumped from the upper reservoir to the lower reservoir through the piping system shown. Determine the power required for the pump if the water flow rate is 60 kg/s. The fittings from pipe Di to pipe D2 and from pipe D2 to pipe D3 can be considered to be standard 90° elbows with velocity in pipe 2 for the friction loss. Data: h = 10 m, h2 = 3 m, L1 water viscosity = 1 cP = 103 kg/m-s, p= 1000 kg/m³. The pipe roughness is 0.05 mm. The pump efficiency is 75%. 50 m, L2 = 300 m, L3 = 2 m, D¡ = 0.2 m, D2= 0.5 m, D3 = 0.03 m, (1) D,, L, D2, L, Globe valve D3, L,
Please solve and answer the question correctly please. Thank you!!
Two tanks A and B are connected by a pipe 30 m long. The first 21 m has a diameter of 75 mm and then is suddenly reduced to 50 mm for the next 9 m. The difference of levels between the tank water levels is 2.40 m. Pipe coefficient f=0.005 and the contraction coefficient at sudden change in area is 0.58. Find all the losses, in terms of velocity v2 at exit from the 50 mm2pipe and hence find rate of flow. Draw the Hydraulic gradient line.
Question 8 download image D The water in a large tank exits through a horizontal circular pipe of diameter D=0.01m and length L=94m. The centre of the exit of the pipe is h=1.0m below the water surface. We can assume that the flow entrance to the pipe is smooth so that there are no minor losses. The flow in the pipe is laminar, the friction factor can be assumed constant and can be found from h fD=64/Rep where the Reynolds number is based on the pipe diameter and mean flow speed in the pipe. Taking frictional losses into account, solve the resulting quadratic equation to calculate the speed of the flow out of the pipe. Give your answer in m/s to 2 decimal places. Use: kinematic viscosity given by v=0.00000114 m²/s density of water given by 1000 kg/m3 acceleration due to gravity of 9.81 m/s² A Moving to another question will save this response. >>
A pipe of 50 mm diameter and 4,5 km length connects two reservoirs whose constant difference of water level is 12 m. A branch pipe 1,25 km long and taken from a point distance of 1,5 km from reservoir A, which leads to reservoir C whose water level is 15 m below that of reservoir A. Find the diameter of the branch pipe so that the flow into both the reservoirs is the same. Assume the coefficient of friction for each pipe, f=0.0075,and neglect minor losses.
I need the answer at 20 minute
Elevation = 100 ft D¸ = 1 ft (1) l (1) e, = 1000 ft D2 = 1 ft lz = 500 ft B V Elevation = %3D 20 ft (2) D3 = 1 ft (3) Elevation = l3 = 400 ft O ft Three open reservoirs are connected by pipes as shown above. It is assumed that the pipe diameter is equal to the friction factor of 0.03. Because theratio of the LIDpipe is large, the minor losses are ignored. Determine the flow in or out of each reservoir! Draw with sketch 5.
A pipe has a diameter D and a friction factor f. Assume that f is constant due to a very large reynolds number. By what percent will the pressure drop in the pipe increase if the volume flow is doubled?
A centrifugal pump delivers water at a rate of 0.03 m³/sec to a height of 18 meters through a pipe of 100 mm diameter and 90 m long. If the overall efficiency of the pump is 73 by find the power required to drive t e pump. (Take f = 0.012).