(7) Calculate the velocity v in branch a K₁ (P₁) Q₁ Qa Qb K₂ _m/s (P₂) Q2

Elements Of Electromagnetics
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The Figure shown below is a parallel pipeline system with two branches used to supply lubricating water to the bearings. The main line and two branches use the same size of pipes. The pressures at section 1 and section 2 are   and  ,  respectively. The resistance coefficients for two bearings are   and  .  The cross section areas of two branch pipes are   .  The energy loss caused by friction can be ignored. The energy loss caused by one bend is  .

(7)   Calculate the velocity     in branch a_________m/s

 

The Figure shown below is a parallel pipeline system with two branches used to supply
lubricating water to the bearings. The main line and two branches use the same size of pipes.
The pressures at section 1 and section 2 are p₁=398.1kPa and p₂=300kPa
1
2
respectively. The resistance coefficients for two bearings are K₁=5 and K₂ = 12. The
cross section areas of two branch pipes are A = A₁ = 1.5x 10-4m². The energy loss
b
caused by friction can be ignored. The energy loss caused by one bend is
h₂=0.2 m.
h
(7) Calculate the velocity v in branch a
K₁
(P₁
K₂
m/s
Transcribed Image Text:The Figure shown below is a parallel pipeline system with two branches used to supply lubricating water to the bearings. The main line and two branches use the same size of pipes. The pressures at section 1 and section 2 are p₁=398.1kPa and p₂=300kPa 1 2 respectively. The resistance coefficients for two bearings are K₁=5 and K₂ = 12. The cross section areas of two branch pipes are A = A₁ = 1.5x 10-4m². The energy loss b caused by friction can be ignored. The energy loss caused by one bend is h₂=0.2 m. h (7) Calculate the velocity v in branch a K₁ (P₁ K₂ m/s
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