Calculate AS" for the following reactions, using standard entropy values from the table below. a. For the reaction 4AI(4) + 302 (9) → 2AI,O;(4) Species S J(mol-K) Al(s) 28.28 O2(9) 205.0 Al,0,(s) 50.95 AS J/K b. For the reaction 4HCN(1) + 502 (9) → 2H,0(9) + 4CO;(9) + 2N, (9) Species S J(mol-K) HCN(1) Oz(9) 112.8 205.0 H,O(g) 188.7 213.7 N2(9) 191.6 AS - J/K

Calculate AS" for the following reactions, using standard entropy values from the table below. a. For the reaction 4AI(4) + 302 (9) → 2AI,O;(4) Species S J(mol-K) Al(s) 28.28 O2(9) 205.0 Al,0,(s) 50.95 AS J/K b. For the reaction 4HCN(1) + 502 (9) → 2H,0(9) + 4CO;(9) + 2N, (9) Species S J(mol-K) HCN(1) Oz(9) 112.8 205.0 H,O(g) 188.7 213.7 N2(9) 191.6 AS - J/K

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Using the standard entropies below, calculate ASºrx (in J/K) for the following reaction. Report your answer to two decimal places in standard notation (i.e. 123.45 J/K). 2Cu₂0(s) + C(s) → 4Cu(s) + CO₂(g) -> Compound so (J mol-¹ K-¹) Cu₂0 (s) 92.37 5.60 33.15 213.74 C (s) Cu (s) CO₂ (g) Submit Answer Tries 0/5
Be sure to answer all parts. Use the table to caleulate AG"_ for the following reactions at 25°C. Species AG (kJ/mol) Mg(s) 0:(8) MgO(s) -569.6 SO,(8) -300.57 so,(3) |-370.53 C,H2(3) 209.2 CO2(3) -394.65 H,O() -237.35 H,O(g) -228.77 (a) 2 Mg(s) + O2(g) →2 MgO(s) kJ (b) 2 SO¿(g) + O2(g) → 2 SO3(g) kJ (c) 2 C,H¿(g) + 5 O,®) → 4 CO,(g) + 2 H,0) kJ
A 135.0 L weather balloon filled with 6.40 mol of helium has a small leak. If the helium leaks at a rate of 10.0 mmol/hr, what is the volume of the balloon after 69.0 hours? L
Gaseous SO2Cl2 reacts with liquid water to form hydrogen chloride gas and liquid sulfuric acid. Using data tabulated in Appendix G of your text, calculate the enthalpy change, in units of kJ/mol, for the formation of 2 mol of liquid sulfuric acid.
For the reaction NH,NO3(aq) –→N½0(g) + 2 H2O(1) AG° = -181.7 kJ and AH° = -149.6 kJ at 321 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 321 K. The entropy change for the reaction of 2.38 moles of NH,NO3(aq) at this temperature would be J/K.
Traduction: Given the reaction: determine the entalpy change for the next ecuation: 8. Dada la reaccion 4AICI3(s) + 302(g) → 2Al2O3(s) + 6CI2(g); AH= -529.0 kJ %3D determine AH para la siguiente rea ión Cl2(g) + %Al2O3(s) %AICI3(s) + ½O2(g) +529.0 kJ +88.2 kJ +176.3 kJ +264.5 kJ a)
For the reaction NH4NO3(aq) 1 N₂O(g) + 2 H₂0 (1) AG° -179.4 kJ and AH = -149.6 kJ at 298 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 298 K. The entropy change for the reaction of 1.51 moles of NH4NO3(aq) at this temperature would be J/K.
A chemical engineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 105.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium.
M Preq 3 Consider the reaction 00 E D 4HCI(g) + O₂(g) 2H₂O(g) + 2Cl₂(8) for which AH° = -114.4 kJ and AS° = -128.9 J/K at 298.15 K. J/K (1) Calculate the entropy change of the UNIVERSE when 1.775 moles of HCI(g) react under standard conditions at 298.15 K. ASuniverse (2) Is this reaction reactant or product favored under standard conditions? Submit Answer (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'. 4 000 000 R F DO LO V % 5 [Review Topics] [References] Use the References to access important values if needed for this question. T Retry Entire Group 8 more group attempts remaining Cengage Learning Cengage Technical Support G 6 B Y H & 7 N U 1 * 8 J M 9 K बैं O < L P Previous Email Instructor Save and Exit { + 11 Next ? } ]
llus_engine.html?ClassID=1653724337# Calculate the change in entropy for the reaction. H2(g) + l2(g) = 2HI(g) Substance S° (J/mol·K) H,(g) 1,(8) HI(g) 130.58 116.73 206.30 AS° = [ ? ] J/mol - K Enter either a + or - sign AND the magnitude in your answer. Enter
As per KMT, which one will have a higher volume at the same temperature and pressure – one mole of Helium OR one mole of Neon?
A chemical engineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 136.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. AH = -2220, kJ J AS = -5426. K C,H, (g) + 50,(8) → 3C0,g) + 4H,0() AG = kJ Which is spontaneous? O this reaction O the reverse reaction O neither ΔΗ 50. ky AS = 6CI, (g) + 2Fe,0.(s)…