c. For the reaction so; (9) + 2H2S(9) → 38(s) + 2H2O(g) Species S" J/(mol·K) SO2 (9) 248.1 H38(9) 205.6 S(s) 32.06 H20(9) 188.7 AS" --185.72 | J/K d. For the reaction 2PB0(a) + N2 (9) → 2Pb(s) + 2NO(9) Species S" J/(mol-K) PbO(s) 66.32 N2(9) Pb(s) 191.6 64.78 NO(g) 210.6 J/K

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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c. For the reaction
so; (9) + 2H2S(g) –→ 38(s) + 2H20(9)
Species S" J/(mol-K)
So, (9)
248.1
H,8(g)
205.6
S(s)
32.06
H20(g)
188.7
AS" -|-185.72
J/K
d. For the reaction
2PBO(s) + N2(9) + 2Pb(s) + 2NO(9)
Species S" J/(mol-K)
PbO(s)
66.32
N2 (9)
191.6
Pb(s)
64.78
NO(g)
210.6
AS
J/K
Transcribed Image Text:c. For the reaction so; (9) + 2H2S(g) –→ 38(s) + 2H20(9) Species S" J/(mol-K) So, (9) 248.1 H,8(g) 205.6 S(s) 32.06 H20(g) 188.7 AS" -|-185.72 J/K d. For the reaction 2PBO(s) + N2(9) + 2Pb(s) + 2NO(9) Species S" J/(mol-K) PbO(s) 66.32 N2 (9) 191.6 Pb(s) 64.78 NO(g) 210.6 AS J/K
Expert Solution
Step 1

The entropy of the reaction can be calculated by standard molar entropies.

So, here “products minus reactants” rule can be used for the purpose.

i.e. the absolute entropy of each reactant and product is multiplied by its stoichiometric coefficient provided in the balanced chemical equation and the sum of entropies of the reactants is subtracted from the sum of entropies of the products.

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