**Problem 21: Thermochemistry**21. Given the following two equations:\[ \text{C}_2\text{H}_5\text{OH(l)} + 3 \text{O}_2\text{(g)} \rightarrow 2 \text{CO}_2\text{(g)} + 3 \text{H}_2\text{O(l)} \quad \Delta H = -1370 \, \text{kJ} \]\[ \text{C}_2\text{H}_4\text{(g)} + 3 \text{O}_2\text{(g)} \rightarrow 2 \text{CO}_2\text{(g)} + 2 \text{H}_2\text{O(l)} \quad \Delta H = -1410 \, \text{kJ} \]**Calculate $\Delta H$ for the reaction:**\[ \text{C}_2\text{H}_4\text{(g)} + \text{H}_2\text{O(l)} \rightarrow \text{C}_2\text{H}_5\text{OH(l)} \quad \Delta H = ? \]**Options:**a. $-2780 \, \text{kJ}$b. $2780 \, \text{kJ}$c. $-40 \, \text{kJ}$d. $40 \, \text{kJ}$ ---### ExplanationTo solve this problem, we need to manipulate the given thermochemical equations to derive the enthalpy change ($\Delta H$) for the target reaction. Consider using Hess's Law, which states that the total enthalpy change in a chemical reaction is the same regardless of the pathway taken, as long as initial and final conditions are the same. The strategy involves reversing and/or multiplying the given equations as necessary to sum to the desired reaction.

Answered: Image /qna-images/answer/a8408aa1-94d0-40cf-80df-39b6d69fed53.jpg

21. Given the following two equations С-Н-ОН(1) + 3 O2(8) → 2 CO2(8) + 3 H2O(1) AH = -1370 kJ СЭНА(8) + 3 Ог(8) → 2 CO2(8) + 2 H2O(1) AH = -1410 kJ Calculate AH for the reaction C2H4(8) + H2O(1) → CH$OH(1) ΔΗ-? %3D a. -2780 kJ b. 2780 kJ c. -40 kJ d. 40 kJ

21. Given the following two equations С-Н-ОН(1) + 3 O2(8) → 2 CO2(8) + 3 H2O(1) AH = -1370 kJ СЭНА(8) + 3 Ог(8) → 2 CO2(8) + 2 H2O(1) AH = -1410 kJ Calculate AH for the reaction C2H4(8) + H2O(1) → CH$OH(1) ΔΗ-? %3D a. -2780 kJ b. 2780 kJ c. -40 kJ d. 40 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Using the following equations, N,0(g)– 2NO2(g) AH° = +57.93 kJ 2NO(g) + O(g) 2NO,(g) AH° = -113.14 kJ %3D calculate the AH° for the following reaction: 2NO(g) + O2(g)– N,0,(g) AH° = kJ
Calculate AGºrxn for the reaction: BaCO3(s)→BaO(s)+CO₂(g) Use the following reactions and given AGºrxn values: Ba(s)+CO₂(g)+1/2O2(g) →BaCO3(s) AG°rxn=-1134.4kJ 2Ba(s)+O₂(g)→2BaO(s), AGºrxn=-520.3kJ BaCO3(s)→BaO(s)+CO₂(g). AGºrxn =
2. Given the following data V(s) + 2 Cl₂(g) → VC14 (1) 1 VCl3(s) → VCl2 (s) + 2 Cl2(g) 2 VC13(s) → VCl₂ (s) + VC14 (1) calculate AH for the reaction: [-580.7 kJ] 3 V(s) + Cl2(g) → VCl3 (s) 2 AH= -569.4 kJ AH = +128.9 kJ ΔΗ = +140.2 kJ I
Given the following equation: 3 2 Al(s) + O2(8) → Al203(s) AH = -2,758 kJ Calculate the AH for the following reaction: 2 Al203(5) → 4 AI(s) + 3 O2(g) 3340 x k)
Consider the following reaction: 3C(s) + 3H2(g) → C3H6(g); AG°= 60.0 kJ and AS° =-256.7 J/K at 298 K What is the equilibrium constant and AH° at 298 K for this reaction? Express AH° in kJ and use 3 significant figures for both answers. AH° = kJ and Keq x 10
Consider the unbalanced equation for the neutralization of acetic acid: αHC2H3O2(aq)+βBa(OH)2(aq) →γH2O(l)+δBa(C2H3O2)2(aq) Balance the equation. Give your answer as an ordered set of numbers α, β, γ, δ. Your answers should reflect the lowest whole-number ratio of coefficients.
Calculate AHrxn for the reaction below. 2 NOCI(g) → N2(g) + 02(g) + Cl2(9) You are given the following set of reactions. 1/2 N2(g) + 1/2 02(g) → NO(g) AH = 90.30 k) NO(g) + 1/2 Cl2(g) → NOCI(g) AH = -38.6 kJ 4.0 kJ
Calculate AH for the reaction 2Sn(s) + O₂(g) → 2SnO(s) Given the following hypothetical data: Sn(s) + O₂(g) → SnO₂ (s) 2SnO(s) + O₂(g) → 2SnO₂ (s) ΔΗ AH = KJ AH AH-581 kJ - 2SnO₂ (s) AH = − 592 kJ
Consider the reaction A →B with AH° = 60.55 kJ/mol,xn and the reaction B -→C with AH = 65.96 kJ/molxn- What should be the AH° in kJ/moln for the reaction A+ C→ 2 B? Report your answer to three decimal places.
Calculate AH for the reaction 4Cu(8) + O₂(g) → 2Cu₂0(8) Given the following hypothetical data: 2Cu(s) + O₂(g) → 2CuO(s) 2Cu₂ 0(8) + 024CuO(s) kj AH= AH = - 312 kJ AH = -340. kJ