For the reaction CACO3(s)- → CaO(s) + CO2(g) AG° = 137.0 kJ and AH = 178.3 kJ at 257 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 257 K. The entropy change for the reaction of 2.36 moles of CaCO3(s) at this temperature would be J/K.
For the reaction CACO3(s)- → CaO(s) + CO2(g) AG° = 137.0 kJ and AH = 178.3 kJ at 257 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 257 K. The entropy change for the reaction of 2.36 moles of CaCO3(s) at this temperature would be J/K.
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![For the reaction
CACO3(s) –→CaO(s) + CO2(g)
AG° = 137.0 kJ and AH° = 178.3 kJ at 257 K and 1 atm.
%3D
This reaction is (reactant, product)
favored under standard conditions at 257 K.
The entropy change for the reaction of 2.36 moles of CACO3(s) at this temperature would be
J/K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2f630dd-ebd8-47cc-8f10-a217d886b05a%2F6b1e2856-d718-4433-af24-86894875a3b2%2F6cv9o8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the reaction
CACO3(s) –→CaO(s) + CO2(g)
AG° = 137.0 kJ and AH° = 178.3 kJ at 257 K and 1 atm.
%3D
This reaction is (reactant, product)
favored under standard conditions at 257 K.
The entropy change for the reaction of 2.36 moles of CACO3(s) at this temperature would be
J/K.
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