C3H18(1) + 2502(g) - 16CO2(9) + 18H20(1) AH°n = -11,020 KJ/mol. iven that AH°{CO2(9)] = -393.5 kJ/mol and AH?{H2O(1)] = -285.8 kJ/mol, calculate the standard enthalpy of formatio O -420 kJ/mol O 22,040 kJ/mol O -210 kJ/mol O 420 kJ/mol O -11,230 kJ/mol

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Octane (C3H18) undergoes combustion according to the following thermochemical equation:
2C3H18(1) + 2502(g)
16CO2(g) + 18H20(1)
°pxn = -11,020 kJ/mol.
Given that AH°{CO2(g)] = -393.5 kJ/mol and AH°{{H2O(1)] = -285.8 kJ/mol, calculate the standard enthalpy of formation of octane.
O -420 kJ/mol
O 22,040 kJ/mol
O - 210 kJ/mol
O 420 kJ/mol
O -11,230 kJ/mol
Transcribed Image Text:Octane (C3H18) undergoes combustion according to the following thermochemical equation: 2C3H18(1) + 2502(g) 16CO2(g) + 18H20(1) °pxn = -11,020 kJ/mol. Given that AH°{CO2(g)] = -393.5 kJ/mol and AH°{{H2O(1)] = -285.8 kJ/mol, calculate the standard enthalpy of formation of octane. O -420 kJ/mol O 22,040 kJ/mol O - 210 kJ/mol O 420 kJ/mol O -11,230 kJ/mol
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