A 90.0 g piece of metal, initially at 98.6°C, is placed into 120.0 g of water initially at 24.3°C. If the final temperature of the water is 34.0°C, what is the specific heat of the metal? (The specific heat of water is 4.18 J/g-°C).

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A 90.0 g piece of metal, initially at 98.6°C, is placed into 120.0 g of water initially at 24.3°C. If the final temperature of the water is 34.0°C, what is the specific heat of the metal? (The specific heat of water is 4.18 J/g·°C).
Transcribed Image Text:A 90.0 g piece of metal, initially at 98.6°C, is placed into 120.0 g of water initially at 24.3°C. If the final temperature of the water is 34.0°C, what is the specific heat of the metal? (The specific heat of water is 4.18 J/g·°C).
**Thermochemical Equations and Enthalpy Determination**

In this problem, we are provided with several thermochemical equations, each with an associated enthalpy change (ΔH°). Our goal is to determine the enthalpy for a specific reaction.

**Given Equations:**

1. \(2 \text{C}_6\text{H}_6 \ (\text{l}) + 15 \text{O}_2 \ (\text{g}) \rightarrow 12 \text{CO}_2 \ (\text{g}) + 6 \text{H}_2\text{O} \ (\text{g})\)  
   \(\Delta H^\circ = -6271 \ \text{kJ/mol}\)

2. \(2 \text{H}_2 \ (\text{g}) + \text{O}_2 \ (\text{g}) \rightarrow 2 \text{H}_2\text{O} \ (\text{g})\)  
   \(\Delta H^\circ = -483.6 \ \text{kJ/mol}\)

3. \(\text{C} \ (\text{s}) + \text{O}_2 \ (\text{g}) \rightarrow \text{CO}_2 \ (\text{g})\)  
   \(\Delta H^\circ = -393.5 \ \text{kJ/mol}\)

**Target Reaction:**

Determine the enthalpy for the reaction:  
\(6 \text{C} \ (\text{s}) + 3 \text{H}_2 \ (\text{g}) \rightarrow \text{C}_6\text{H}_6 \ (\text{l})\).

**Explanation:**

To determine the enthalpy change for the target reaction, a common approach in thermochemistry is to apply Hess's Law, which states that the enthalpy change for a reaction is the same regardless of the pathway taken. Use the provided equations to construct the target reaction by reversing or scaling the given reactions as necessary and sum the respective enthalpy changes.
Transcribed Image Text:**Thermochemical Equations and Enthalpy Determination** In this problem, we are provided with several thermochemical equations, each with an associated enthalpy change (ΔH°). Our goal is to determine the enthalpy for a specific reaction. **Given Equations:** 1. \(2 \text{C}_6\text{H}_6 \ (\text{l}) + 15 \text{O}_2 \ (\text{g}) \rightarrow 12 \text{CO}_2 \ (\text{g}) + 6 \text{H}_2\text{O} \ (\text{g})\) \(\Delta H^\circ = -6271 \ \text{kJ/mol}\) 2. \(2 \text{H}_2 \ (\text{g}) + \text{O}_2 \ (\text{g}) \rightarrow 2 \text{H}_2\text{O} \ (\text{g})\) \(\Delta H^\circ = -483.6 \ \text{kJ/mol}\) 3. \(\text{C} \ (\text{s}) + \text{O}_2 \ (\text{g}) \rightarrow \text{CO}_2 \ (\text{g})\) \(\Delta H^\circ = -393.5 \ \text{kJ/mol}\) **Target Reaction:** Determine the enthalpy for the reaction: \(6 \text{C} \ (\text{s}) + 3 \text{H}_2 \ (\text{g}) \rightarrow \text{C}_6\text{H}_6 \ (\text{l})\). **Explanation:** To determine the enthalpy change for the target reaction, a common approach in thermochemistry is to apply Hess's Law, which states that the enthalpy change for a reaction is the same regardless of the pathway taken. Use the provided equations to construct the target reaction by reversing or scaling the given reactions as necessary and sum the respective enthalpy changes.
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