Suppose you heat a metal object with a mass of 31.8 g to 96.8 °C and transfer it to a calorimeter containing 100.0 g of water at 18.7 °C. The water and metal reach a final temperature of 22.9 °C. METAL What is the specific heat of the metal in J ? g.°C

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**Heat Transfer and Specific Heat Calculation**

**Scenario:**
A metal object with a mass of 31.8 grams is heated to a temperature of 96.8°C. This metal is then transferred to a calorimeter containing 100.0 grams of water, initially at 18.7°C. Once equilibrium is reached, the final temperature of both the metal and the water is 22.9°C.

**Diagram Description:**
The diagram shows a calorimeter, typically represented as a container filled with water. Inside the container, there is a metal object submerged in the water. Above the water, a thermometer is inserted to measure the temperature change. The metal is labeled, and arrows indicate the heat exchange between the metal and the water.

**Calculation Goal:**
Determine the specific heat of the metal in joules per gram per degree Celsius (J/g·°C).

**Understanding the Concept:**
The heat lost by the metal equals the heat gained by the water. Using this principle, along with the known masses and temperature changes, you can calculate the specific heat of the metal.
Transcribed Image Text:**Heat Transfer and Specific Heat Calculation** **Scenario:** A metal object with a mass of 31.8 grams is heated to a temperature of 96.8°C. This metal is then transferred to a calorimeter containing 100.0 grams of water, initially at 18.7°C. Once equilibrium is reached, the final temperature of both the metal and the water is 22.9°C. **Diagram Description:** The diagram shows a calorimeter, typically represented as a container filled with water. Inside the container, there is a metal object submerged in the water. Above the water, a thermometer is inserted to measure the temperature change. The metal is labeled, and arrows indicate the heat exchange between the metal and the water. **Calculation Goal:** Determine the specific heat of the metal in joules per gram per degree Celsius (J/g·°C). **Understanding the Concept:** The heat lost by the metal equals the heat gained by the water. Using this principle, along with the known masses and temperature changes, you can calculate the specific heat of the metal.
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