b My Questions | bartleby 101 Chem101 app.101edu.co Submit Question 25 of 29 Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g). → CH4 (g) AH° = -74.9 kJ/mol %3D | kJ/mol 1 3 4 8 9. +/- x 100 1:22 PM O Type here to search 12/9/2019 LO

b My Questions | bartleby 101 Chem101 app.101edu.co Submit Question 25 of 29 Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g). → CH4 (g) AH° = -74.9 kJ/mol %3D | kJ/mol 1 3 4 8 9. +/- x 100 1:22 PM O Type here to search 12/9/2019 LO

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Given the information below: 2C(s) + 2H20(g) CH4(g) + CO2(g) AH° = 35.3 kJ 2C(s) + 2H20(g) 2C0(g) + 2H2(g) AH° = 462.6 kJ -> CH4(g) + H20(g)→ CO(g) + 3H2(g) AH° = -61.2 kJ %3D Calculate the enthalpy of reaction for the reaction below (in kJ) Co(g) + H20(g) → CO2(g) + H2(g) -366,1 kJ -488.5kJ -436.7 kJ +488.5 kJ +436,7 kJ +366.1kJ O0 0 O OO
Question 4 of 17 Using the equations SrO (s) + CO₂ (g) → SrCO3 (s) AH° = -234 kJ/mol 2 Sr(s) + O₂(g) → 2 SrO (s) AH° = -1184 kJ/mol CO₂ (g) → C(s) + O₂ (g) AH° = 394 kJ/mol Determine the molar enthalpy (in kJ/mol) for the reaction 1 4 7 +/- 2 SrCO3 (s) → 2 Sr (s) + 2 C(s) + 3 O₂ (g). 2 5 8 Submit kJ/mol 3 60 9 O Tap here or pull up for additional resources XU x 100
Using the equations Ca(s) + 1/2 0, (g) → CaO (s) AH° = -450 kJ/mol CO, (g) → C (s) + O, (g) AH° = 394 kJ/mol Determine the enthalpy for the reaction C(s) + 2 CaO(s) → CO, (g) + 2 Ca(s). KJ/mol 1 2 3 6. C 7 8 9. +/- х 100 4.
Are the reactions endothermic or exothermic? What observation supports this?
Using the equations H₂ (g) + Cl₂ (g) → 2 HCI (g) AH° = -184.6 kJ/mol C (s) + 2 Cl₂ (g) →→ CCI (g) AH° = -95.7 kJ/mol Determine the molar enthalpy (in kJ/mol) for the reaction C (s) + 4 HCI (g) → CCI (g) + 2 H₂ (g). 4 2
Using the equations determine the enthalpy for the reaction
Given the data below, H°, for the reaction rxn 3C12 (g) + PH3 (g) → PCI3 (g) + 3HCI (g) is kJ. AH° (PCI3 (g) = -288.07 kJ/mol AH°F (HCI (g)) = -92.30 kJ/mol AH°r (PH3 (g)) = 5.40 kJ/mol 570.37 O The AH°, of Cl2 (g) is needed for the calculation. -385.77 385.77 -570.37
What is the enthalpy change when 8.20 moles ammonium chloride form in the following equation? N2 (g) + 4 H2 (g) + Cl2 (g) --> 2 NH4Cl (s) Delta H = – 628.8 kJ a. – 2.58 x 103 kJ b. – 1.29 x 103 kJ c. + 314.4 kJ d. – 314.4 kJ e. – 628.8 kJ f. – 5.16 x 103 kJ g. none of these d. – 314.4 kJ
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Question 9 of 24 Determine the enthalpy of reaction for HCI(g) + NaNO2(s) → HNO2(1) + NaCI(s) 2NACI(s) + H2O(1) → 2HCI(g) + Na20(s) AH° = -507.1 kJ/mol NO(g) + NO2(g) + Na,0(s) → 2NANO2(s) AH° = -427.0 kJ/mol NO(g) + NO2(g) → N20(g) + O2(g) AH° = -43.01 kJ/mol 2HNO2(1) → N,0(g) + O2(g) + H2O(1) AH° = +34.02 kJ/mol %3D %3D %3D Tap here or pull up for additional resources @ #3 24 & 2 8.