b My Questions | bartleby 101 Chem101 app.101edu.co Submit Question 25 of 29 Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g). → CH4 (g) AH° = -74.9 kJ/mol %3D | kJ/mol 1 3 4 8 9. +/- x 100 1:22 PM O Type here to search 12/9/2019 LO

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Question 25 of 29
Using the equations
N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol
C(s) + 2 H2 (g) →
H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol
Determine the enthalpy for the reaction
CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g).
→ CH4 (g) AH° = -74.9 kJ/mol
%3D
| kJ/mol
1
3
4
8
9.
+/-
x 100
1:22 PM
O Type here to search
12/9/2019
LO
Transcribed Image Text:b My Questions | bartleby 101 Chem101 app.101edu.co Submit Question 25 of 29 Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g). → CH4 (g) AH° = -74.9 kJ/mol %3D | kJ/mol 1 3 4 8 9. +/- x 100 1:22 PM O Type here to search 12/9/2019 LO
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