**Calculation of Reaction Enthalpy (ΔH°rxn)**Given the data below, the standard enthalpy change of reaction (ΔH°rxn) for the given chemical reaction can be calculated:Reaction:\[ 3\text{Cl}_2 \text{(g)} + \text{PH}_3 \text{(g)} \rightarrow \text{PCl}_3 \text{(g)} + 3\text{HCl (g)} \]The ΔH°rxn is _______ kJ.**Standard Enthalpies of Formation:**- ΔH°f (PCl₃ (g)) = -288.07 kJ/mol- ΔH°f (HCl (g)) = -92.30 kJ/mol- ΔH°f (PH₃ (g)) = 5.40 kJ/molChoose the correct answer for the ΔH°rxn:- ○ 570.37 kJ- ○ The ΔH°f of Cl₂ (g) is needed for the calculation.- ○ -385.77 kJ- ○ 385.77 kJ- ○ -570.37 kJ**Note:** To solve this problem, use the standard enthalpy of formation values and apply Hess's law or the formula for the enthalpy of reaction:\[ \Delta H^\circ_{rxn} = \sum \Delta H^\circ_f (\text{products}) - \sum \Delta H^\circ_f (\text{reactants}) \]

Answered: Image /qna-images/answer/f0bc412b-b8fc-42e2-bd10-9727bc8cf6ff.jpg

Given the data below, H°, for the reaction rxn 3C12 (g) + PH3 (g) → PCI3 (g) + 3HCI (g) is kJ. AH° (PCI3 (g) = -288.07 kJ/mol AH°F (HCI (g)) = -92.30 kJ/mol AH°r (PH3 (g)) = 5.40 kJ/mol 570.37 O The AH°, of Cl2 (g) is needed for the calculation. -385.77 385.77 -570.37

Given the data below, H°, for the reaction rxn 3C12 (g) + PH3 (g) → PCI3 (g) + 3HCI (g) is kJ. AH° (PCI3 (g) = -288.07 kJ/mol AH°F (HCI (g)) = -92.30 kJ/mol AH°r (PH3 (g)) = 5.40 kJ/mol 570.37 O The AH°, of Cl2 (g) is needed for the calculation. -385.77 385.77 -570.37

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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